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____ [38]
3 years ago
11

35% of what number is 35?

Mathematics
2 answers:
ZanzabumX [31]3 years ago
6 0
0.35 or fraction 35/100
EleoNora [17]3 years ago
6 0
Thats a question i jhuss answered 

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ABCD is a quadrilateral inscribed in a circle, as shown below: Circle O is shown with a quadrilateral ABCD inscribed inside it.
kogti [31]

Answer:

B. (x + 16) + (6x − 4) = 180

Step-by-step explanation:

The Cyclic Quadrilateral Theorem states that for a quadrilateral in a circle, the opposite angles will equal 180 degrees. So therefore you can conclude:

∠A + ∠C = 180° which would be (x + 16) + (6x - 4) = 180°

∠B + ∠D =180° which would be x + (2x - 16) = 180°

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3 years ago
How do you solve 15 = 7 - x
oee [108]
15 + 8 = 7, X = 8. X equals 8.
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2 years ago
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2 years ago
A circle has a radius of 6 ft.
den301095 [7]
I'm assuming that 5π3 is in fact 5π/3

convert radian to degrees:

5π / 3 = 5(180°) / 3 = 900° / 3 = 300°

Area of the circle = π r²
A = 3.14 * (6 ft)²
A = 3.14 * 36 ft²
A = 113.04 ft²

Area of the sector:

113.04 ft²  * 300°/360° = 94.2 ft²

The area of the sector formed by a central angle measuring 5π/3 radian is 94.2 ft²
8 0
3 years ago
Read 2 more answers
If U = {x: X € N, 1 &lt; × &lt; 15)
Inessa05 [86]

Answer:

Step-by-step explanation:

Given:

U = {x: X € N, 1 < × < 15) = {1,2,3,4,5,6,7,8,9,10,11,12,13,14,15}

A = {2,4,6,8,10,12,14}

B = {3,6,9,12,15}

C = {5,10,15}

(a) Verify A(BnB)=(AUB)(AUB)

A U (B n B)

=  {2,4,6,8,10,12,14} U (  {3,6,9,12,15} n  {3,6,9,12,15} )

=  {2,4,6,8,10,12,14} U {3,6,9,12,15}

=  {2,3,4,6,8,9,10,12,14,15}

( A U B) n (A U B)

= {2,3,4,6,8,9,10,12,14,15} n {2,3,4,6,8,9,10,12,14,15}

= {2,3,4,6,8,9,10,12,14,15}

Therefore

A U (B n B)  =  ( A U B) n (A U B)

verifies

(b) Verify An(BUC)=(AnB)u(AnC)

A n ( B U C)

=  {2,4,6,8,10,12,14} n ( {3,6,9,12,15} U {5,10,15} )

=  {2,4,6,8,10,12,14} n {3,5,6,9,10,12,15}

= {6,10,12}

( A n B ) U ( A n C )

= ( {2,4,6,8,10,12,14} n {3,6,9,12,15} ) U ( {2,4,6,8,10,12,14} n {5,10,15} )

= {6,12} U {10}

= {6,10,12}

Therefore

A n ( B U C) = ( A n B ) U ( A n C )

verifies

(c) Verify AU(BUC)=(AUB)U(AUC)​

AU(BUC)

=  {2,4,6,8,10,12,14}U{3,6,9,12,15}U{5,10,15}

= {2,3,4,5,6,8,9,10,12,14,15}

(AUB)U(AUC)​

=  ({2,4,6,8,10,12,14}{3,6,9,12,15})U({2,4,6,8,10,12,14}U{5,10,15})

= {2,3,4,6,8,9,10,12,14,15}U{2,4,5,6,8,10,12,14,15}

= {2,3,4,5,6,8,9,10,12,14,15}

Therefore

AU(BUC)=(AUB)U(AUC)​

verifies

5 0
3 years ago
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