Answer:
4x^5−15x^3−11x−1
Step-by-step explanation:
Simplify the expression. 4x^5−15x^3−11x−1
Answer:
AB ≈ 15.7 cm, BC ≈ 18.7 cm
Step-by-step explanation:
(1)
Using the Cosine rule in Δ ABD
AB² = 12.4² + 16.5² - (2 × 12.4 × 16.5 × cos64° )
= 153.76 + 272.25 - (409.2 cos64° )
= 426.01 - 179.38
= 246.63 ( take the square root of both sides )
AB = 
≈ 15.7 cm ( to 1 dec. place )
(2)
Calculate ∠ BCD in Δ BCD
∠ BCD = 180° - (53 + 95)° ← angle sum in triangle
∠ BCD = 180° - 148° = 32°
Using the Sine rule in Δ BCD
= 
= 
( cross- multiply )
BC × sin32° = 12.4 × sin53° ( divide both sides by sin32° )
BC = 
≈ 18.7 cm ( to 1 dec. place )
Answer:
Yes, Amanda has enough materials to make the concrete mix.
Step-by-step explanation:
Total units = 1+3+5
= 9
9 units = 630kg
1 unit = 630kg ÷ 9
= 70kg (Less than 80kg of cement, more than enough)
3 units = 3 × 70kg
= 210kg (Less than 215kg of sand, more than enough sand)
5 units = 5 × 70kg
= 350kg (Less than 370kg of gravel, more than enough gravel)
Answer:
42
Step-by-step explanation:
The height of the pole is 4 times shorter than the length of the shadow 20÷5=4
The height of the building must be 4 times shorter than its shadow length 168÷4=42
Answer:
36
Step-by-step explanation:
The angle b is a right angle which is divided into 2. So, each angle would measure 45 degree. (90 / 2 = 45)
tan 45 = 1
\AD\ = 100 - 64 = 36
to find x , remember SOCAHTOA
tan would be used because we have the vale of the opposite angle and we want to find the value of the adjacent angle
Tan 45 = opposite / adjacent
1 = 36/x
x = 36
