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3 years ago

Please help. I don't understand this. Thanks.

Mathematics

1 answer:

neonofarm [45]3 years ago

4 0

Yes;k=-3 and y=-3x is the answer because 2 x -3 = -6 -3 x -3 = -9 and etc..

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Help please I’ll mark you brainliest

prohojiy [21]

Subtract any number from the next one.
-1 - (-6)
4 - (-1)
9 - 4
14 - 9

All of the above subtractions give the same answer.
That answer is the common difference.

3 0

3 years ago

Kelly is having a party. She wants to make punch. The recipe for punch uses 3 pints of pineapple juice, 5 cups or orange juice,

Maurinko [17]

No, because if you add it up all together her recipe does not call for 20 cups.

8 0

3 years ago

A rocket is launched from a tower. The height of the rocket, y in feet, is related to the time after launch, x in seconds, by th

irga5000 [103]

Answer:

The rocket hits the ground at a time of 11.59 seconds.

Step-by-step explanation:

The height of the rocket, after x seconds, is given by the following equation:

$y = -16x^2 + 177x + 98$

It hits the ground when $y = 0$ , so we have to find x for which $y = 0$ , which is a quadratic equation.

Finding the roots of a quadratic equation:

Given a second order polynomial expressed by the following equation:

$ax^{2} + bx + c, a\neq0$ .

This polynomial has roots $x_{1}, x_{2}$ such that $ax^{2} + bx + c = a(x - x_{1})*(x - x_{2})$ , given by the following formulas:

$x_{1} = \frac{-b + \sqrt{\bigtriangleup}}{2*a}$

$x_{2} = \frac{-b - \sqrt{\bigtriangleup}}{2*a}$

$\bigtriangleup = b^{2} - 4ac$

In this question:

$y = -16x^2 + 177x + 98$

$-16x^2 + 177x + 98 = 0$

$a = -16, b = 177, c = 98$

$\bigtriangleup = 177^{2} - 4(-16)(98) = 37601$

$x_{1} = \frac{-177 + \sqrt{37601}}{2*(-16)} = -0.53$

$x_{2} = \frac{-177 - \sqrt{37601}}{2*(-16)} = 11.59$

Since time is a positive measure, the rocket hits the ground at a time of 11.59 seconds.

4 0

3 years ago

For quadrilateral ABCD, determine the most precise name for it. A(-2,3), B(9,3), C(5,6) and D(2,6). Show your work and explain.

horsena [70]

To solve this problem you must apply the proccedure shown below:

1. You have the following points given in the problem above:

A<span>(-2,3), B(9,3), C(5,6) and D(2,6)

2. When you plot them, you obtain the figure shown in the graph attached.

3. Therefore, as you can see, the answer is: the figure is a trapezoid, which is define as a quadrilateral with two parallel sides.</span>

8 0

3 years ago

A car braked with a constant deceleration of 64 ft/s2, producing skid marks measuring 50 ft before coming to a stop. How fast wa

vitfil [10]

Answer:

The initial speed of the car was 80 ft/s.

Step-by-step explanation:

The deceleration is the rate at which the car speed decreases. In this case the speed of the car goes all the way down to 0 ft/s and in order to do that it travelled 50 ft. So we will call the initial speed at which the car started to brake "v_0" and use Torricelli's equation to find it. The equation is given by:

v^2 = (v_0)^2 + 2*a*S

Where v is the final speed, v_0 is the initial speed, a is the rate of acceleration and S is the space travelled. Using the values that the problem gave to us we have:

0^2 = (v_0)^2 - 2*64*50

0 = (v_0)^2 - 6400

(v_0)^2 = 6400

v_0 = sqrt(6400) = 80 ft/s

Notice that in this case "a" was negative, since the car was decelerating instead of accelerating.

The initial speed of the car was 80 ft/s.

4 0

3 years ago

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