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3 years ago

Please help. I don't understand this. Thanks.

Mathematics

1 answer:

neonofarm [45]3 years ago

4 0

Yes;k=-3 and y=-3x is the answer because 2 x -3 = -6 -3 x -3 = -9 and etc..

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What is the greatest common factor of 39 and 65 list all the factors

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Answer:

Step-by-step explanation:

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3 years ago

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Assume that the probability of a defective computer component is 0.02. Components arerandomly selected. Find the probability tha

solmaris [256]

Answer:

0.0177 = 1.77% probability that the first defect is caused by the seventh component tested.

The expected number of components tested before a defective component is found is 50, with a variance of 0.0208.

Step-by-step explanation:

Assume that the probability of a defective computer component is 0.02. Components are randomly selected. Find the probability that the first defect is caused by the seventh component tested.

First six not defective, each with 0.98 probability.

7th defective, with 0.02 probability. So

$p = (0.98)^6*0.02 = 0.0177$

0.0177 = 1.77% probability that the first defect is caused by the seventh component tested.

Find the expected number and variance of the number of components tested before a defective component is found.

Inverse binomial distribution, with $p = 0.02$

Expected number before 1 defective(n = 1). So

$E = \frac{n}{p} = \frac{1}{0.02} = 50$

Variance is:

$V = \frac{np}{(1-p)^2} = \frac{0.02}{(1-0.02)^2} = 0.0208$

The expected number of components tested before a defective component is found is 50, with a variance of 0.0208.

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3 years ago

Find the length of arc XW. Round your answer to the nearest hundredth.

Luda [366]

Answer:

15.08 m

Step-by-step explanation:

The angle XZW :

XZW + 108° = 180°

XZW = 180° - 108°

XZW = 72°

Length of an arc = θ / 360 * πd

d = diameter = XV = 24

Length of arc XW = (72/360) * π * 24

Length of arc XW = 15.0796

Length of XW = 15.08 m

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3 years ago

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Answer:

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<h2> Don't sweat here is a video link too </h2>

Compounding Continuously Pert Formula

https://youtu.be/dFsBfi9W7sQ

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Answer:

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