Answer:
Step-by-step explanation:
We want to rewrite
in the form
We expand to get:
Regroup similar terms:
Simplify:
This is now of the form
where a=23.75 and b=76.24
Answer:
The mean and the standard deviation of the number of students with laptops are 1.11 and 0.836 respectively.
Step-by-step explanation:
Let <em>X</em> = number of students who have laptops.
The probability of a student having a laptop is, P (X) = <em>p</em> = 0.37.
A random sample of <em>n</em> = 30 students is selected.
The event of a student having a laptop is independent of the other students.
The random variable <em>X</em> follows a Binomial distribution with parameters <em>n</em> and <em>p</em>.
The mean and standard deviation of a binomial random variable <em>X</em> are:
Compute the mean of the random variable <em>X</em> as follows:
The mean of the random variable <em>X</em> is 1.11.
Compute the standard deviation of the random variable <em>X</em> as follows:
The standard deviation of the random variable <em>X</em> is 0.836.
Answer:
-1 1/8
Step-by-step explanation:
-3/4 / -8/12
= -3/4 * -12/8
= -3*12 / -4*8
= -36/32
= -1 4/32
= -1 1/8
Answer:
-4.2, -3.5, -2.1, -1.5, -1, -0.5, 0.5, 3.5, 4.8
Step-by-step explanation: