3 years ago

What is theâ€‹ slope-intercept form of the equation of theâ€‹ line?

Mathematics

1 answer:

vovikov84 [41]3 years ago

8 0

Slope intercept form is y=mx+b

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Using cylindrical coordinates,

$\displaystyle\int_{x=0}^{x=\sqrt3}\int_{y=0}^{y=\sqrt{3-x^2}}\int_{z=5+2x^2+2y^2}^{z=11}\mathrm dz\,\mathrm dy\,\mathrm dx$
$\displaystyle=\int_{\theta=0}^{\theta=\pi/2}\int_{r=0}^{r=\sqrt3}\int_{z=5+2r^2}^{z=11}r\,\mathrm dz\,\mathrm dr\,\mathrm d\theta$
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Answer: x = 0, y = 7

-x+y=7

add x to both sides

y=x+7

plug this in for y in the other equation

6x-(x+7)=-7

simplify

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simplify

5x-7=-7

add 7 to both sides

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divide both sides by 5

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plug in to one of the equations to find y

-(0)+y=7

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Therefore, x=0 and y=7.

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