The answer should be 8+[(2^2)+3]-5
Hope this helps!
<h3>
<u>Answer</u><u>:</u><u>-</u></h3>
192 cm²
<h3>
<u>Step</u><u> </u><u>by</u><u> step</u><u> explanation</u><u> </u><u>:</u><u>-</u></h3>
Let us take the height be x , then its side = x + 4. Now half of base will be 12 cm .
<u>According</u><u> to Pythagoras Theorem :- </u>
=> base² + perpendicular ² = hypontenuse ²
=> 12² + x² = (x+4)²
=> 144 + x² = x² + 16 + 8x
=> 8x = 144-16
=> 8x = 128
=> x = 128/8
=> x = 16 cm .
Hence the height of ∆ is 16 cm .So the area will be half the product of base and altitude.
= 1/2 * 16 cm * 24cm .
= 192 cm²
<h3>
<u>★</u><u> </u><u>Hence</u><u> </u><u>the</u><u> </u><u>area</u><u> </u><u>of</u><u> </u><u>the </u><u>tria</u><u>ngle</u><u> is</u><u> </u><u>1</u><u>9</u><u>2</u><u> </u><u>cm²</u><u> </u><u>.</u></h3>
The first option reduces to 1 and the second one reduces to -1.
Answer:
Step-by-step explanation:
1) Mark two points on the line in the graph.
2) Determine the rise and run. Rise ---> difference in y-coordinates. (y2-y1)
Run -----> difference in x-coordinates (x2 - x1)
3) Plugin the values in the below mentioned formula.

1.If slope = 0, then the line is parallel to x-axis.
2. If slope is undefined, then the line is parallel to y-axis.
3. If slope is +ve, then the line slant upwards and if slope = -ve, then the line slant downwards.
Answer: Y=-5x+30
Step-by-step explanation:
First, you have to find the slope of graph so you find the rise over run Y/X. Since the X values are being measured by 1’s, and the Y values are being measure by 5’s, your slope would be -5 (not 5 as the graph line is decreasing therefore it is negative). To find b, you find the Y intercept of the graph (where Y is when X=0) and in this case, the y intercept is 30. So the equation that describes what is occurring in the graph is Y=-5x+30 as a linear equation is written as Y=mx+b. You can check If the equation is correct by substituting the x and y values of a specific coordinate point on the graph. For example: 25= -5(1)+30. This gives you 25=25 so the equation is correct.