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sweet [91]
3 years ago
11

Which function will have a y-intercept at -1 and an amplitude of 2?

Mathematics
2 answers:
Anna35 [415]3 years ago
6 0
The first and 3rd choices are just sin and cos waves, with amplitude of 1 .
So it has to be the 2nd or 4th choice.

The y-intercept is the point on the graph where x=0.
So if the y-intercept is -1, that just means that  f(0)=-1 .
So let's test the two choices:

                                   f(x) = -2 sin(x) - 1

                                   f(0) = -2 sin(0) - 1
sin(0) = 0  so
                                   f(0) = -2 (0)    - 1 .
That looks like it works.
Just to be sure, let's check the other possible choice.

                                  f(x) = -2 cos(x) - 1

                                 f(0) = -2 cos(0) - 1

cos(0) = 1     so         f(0) = -2 (1)      - 1  =  -3 .  

Beautiful !  The y-intercept of choice-2 is -1,
and the y-intercept of choice-4 is  -3.  The answer is choice-2.
baherus [9]3 years ago
5 0

Answer:

the answer is b

Step-by-step explanation:

Im just typing this so it knows that I properly explained

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X+7+=-14<br><br> ASAP! PLease!
umka21 [38]

Hey there!

Answer = -21

Explanation:

Let's solve your equation step-by-step.

x + 7 = -14

Subtract seven from both sides:

x + 7 - 7 = -14 - 7

x = -21

So therefore, that is how you found your answer: x = -21

8 0
3 years ago
Read 2 more answers
A school administrator will assign each student in a group of n students to one of m classrooms. If 3 &lt; m &lt; 13 &lt; n, is
tatiyna

Answer:

Hence to get same number of students in each classroom,the sufficient condition is that assign 13n students to each classroom.

Step-by-step explanation:

Given:

There are m classrooms and n be the students

3<m<13<n.

To Find:

Whether it is possible to assign each of n students to one of m classrooms with same no.of students.

Solution:

This problem is related to p/q form  has to be integer in order to get same no of students assigned to the classroom.

As similar as ,n/m ratio

So 1st condition is that,

If it is possible to assign the n/m must be integer and n should be multiple of m,

when we assign 3n students to m classrooms ,we cannot say that 3n/m= integer so that  n is greater than 13 i.e n=14 and m=6

hence they are not multiple of each other so they will not make same students in each classrooms.

Otherwise,n=14 and m=7 they will give same number but this condition is not sufficient condition to assign the student.

So 2nd condition is that ,

When we assign 13n students to m classrooms, as 13 is prime number and

3<m<13 which implies the 13n/m to be integer so n and m must be multiple of each other.

Suppose n=20 and m=5 classrooms

then 13*20=260 ,

260/5=52 students in each classroom,

4 0
3 years ago
3 square root of 1/125
olasank [31]

3 square root of 1/125

is 1/5

3 0
3 years ago
The x-axis contains the base of an equilateral triangle RST. The origin is at S. Vertex T has coordinates (2h, 0) and the y-coor
frosja888 [35]
For the first part remember that an equilateral triangle is a triangle in which all three sides are equal & all three internal angles are each 60°. <span>So x-coordinate of R is in the middle of ST = (1/2)(2h-0) = h
And for the second </span><span> since this is an equilateral triangle the x coordinate of point R is equal to the coordinate of the midpoint of ST, which you figured out in the previous answer. Hope this works for you</span> 
7 0
3 years ago
Read 2 more answers
Suppose that 50% of all babies born in a particular hospital are boys. If 6 babies born in the hospital are randomly selected, w
WINSTONCH [101]

Using the binomial distribution, it is found that there is a 0.3438 = 34.38% probability that fewer than 3 of them are boys.

<h3>What is the binomial distribution formula?</h3>

The formula is:

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

C_{n,x} = \frac{n!}{x!(n-x)!}

The parameters are:

  • x is the number of successes.
  • n is the number of trials.
  • p is the probability of a success on a single trial.

In this problem, the values of the parameters are given as follows:

n = 6, p = 0.5.

The probability that fewer than 3 of them are boys is given by:

P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2)

In which:

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{6,0}.(0.5)^{0}.(0.5)^{6} = 0.0156

P(X = 1) = C_{6,1}.(0.5)^{1}.(0.5)^{5} = 0.0938

P(X = 2) = C_{6,2}.(0.5)^{2}.(0.5)^{4} = 0.2344

Then:

P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2) = 0.0156 + 0.0938 + 0.2344 = 0.3438

0.3438 = 34.38% probability that fewer than 3 of them are boys.

More can be learned about the binomial distribution at brainly.com/question/24863377

#SPJ1

7 0
2 years ago
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