Question

The rectangle below has an area of x^2-16 square meters and a width of x+4 meters.

Answer 1

X^2-16 is a difference of squares of the form:

(a^2-b^2) which always factors to:

(a+b)(a-b), in this case we have:

(x+4)(x-4), we are told that width is (x+4) so the length is:

(x-4)

Answer 2

Hello Mate!

$Area=LW$
$x^2-16=L(x+4)$
Remember difference of 2 perfect squares to factor $x^2-16$
$(x-4)(x+4)=L(x+4)$
Divide both sides by $(x+4)$
$x-4=L$

Therefore, $length=x-4$

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