1. bc/3 + a/xy + 3/ab
= b^2cxya + 3a^2b + 9xy/3xyab
2. (5/3y) + 2y - 12
=11/3y - 2
3. ?
Hope this helps and right! :)) Good luck
Answer:
Step-by-step explanation:
the zeroes of a function basically mean when y = 0, so basically the x-intercept(s)
in this case, the zeroes are 3 and 6
Answer:
1/2
Step-by-step explanation:
Answer: (3x + 11y)^2
Demonstration:
The polynomial is a perfect square trinomial, because:
1) √ [9x^2] = 3x
2) √121y^2] = 11y
3) 66xy = 2 *(3x)(11y)
Then it is factored as a square binomial, being the factored expression:
[ 3x + 11y]^2
Now you can verify working backwar, i.e expanding the parenthesis.
Remember that the expansion of a square binomial is:
- square of the first term => (3x)^2 = 9x^2
- double product of first term times second term =>2 (3x)(11y) = 66xy
- square of the second term => (11y)^2 = 121y^2
=> [3x + 11y]^2 = 9x^2 + 66xy + 121y^2, which is the original polynomial.
