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alina1380 [7]
3 years ago
5

The amount of medicine, in milliliters, that a veterinarian prescribes is proportional to the weight, in kilograms, of a dog as

shown on the graph.
What is the unit rate in milliliters per kilogram?
Mathematics
1 answer:
tamaranim1 [39]3 years ago
6 0

Answer: 1.75

Step-by-step explanation:

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Can someone help me solve this and put this on a graph. Just one problem may help.
Sauron [17]
I thought of it as answering a regular equation and imagine it's equal signs but when your done solving you with have like ex x<5 and where ever the butt of the arrow is pointing is where the lines goes if there's ano equal sign below it then it is includive
3 0
3 years ago
If m∠NOP = 24 and m∠NOQ = 110, what is m∠POQ? Angle N O Q divided into two unequal angles by ray O P. A. 62 B. 86 C. 134 D. 156
Dmitrij [34]

Answer:

<em>B. 86 degrees</em>

Step-by-step explanation:

Given the following angles:

m∠NOQ = 110

m∠NOP = 24

Using the addition postulate:

m∠NOQ =  m∠NOP + m∠POQ

110 = 24 + m∠POQ

m∠POQ = 110 - 24

m∠POQ = 86

<em>Hence the measure of m∠POQ is 86 degrees</em>

5 0
2 years ago
For each of the -3.3 trials, and in the same sequence in which you entered the freezing points, enter your calculated values for
dedylja [7]

Answer:

The morality of the solution is calculated as 0.859 m. We are required to determine the freezing point depression constant of pure water. The freezing point depression of the solution is given as

T_{f}  = T_{p}  -T_{s} = K_{f} * (morality of solution)

T_{p} and T_{s} are the freezing points of the pure solvent (water, 0°C) andK_{f} = freezing point depression constant of water. Therefore,

T_{f}  = K_{f} *(0.859 m)

=====> (0°C) – (3.00°C) = K_{f}  *(0.859 m)

=====> -3.00°C = K_{f}  *(0.859 m)

Ignore the negative sign (since K_{f} is positive) and get

K_{f} = (3.00°C) / (0.859 m) = 3.492°C/m

The freezing point depression constant of the solvent is 3.5°C kg/mole  

3.5 K.kg/mole (temperature differences are the same in Celsius and Kelvin scales).

3 0
2 years ago
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gayaneshka [121]
(-9)+(-6)+(-4)+(-1) is the expression and (-20) is the sum
3 0
3 years ago
There are 5 questions on a multiple choice exam, each with five possible answers. If a student guesses on all five questions, wh
Mrac [35]

Answer:

20.5\%

Step-by-step explanation:

Let's write out a case for two specific questions being correct and the rest being incorrect:

\frac{1}{5}\cdot \frac{1}{5}\cdot \frac{4}{5}\cdot \frac{4}{5}\cdot \frac{4}{5},

The \frac{1}{5} represents the chances of getting the question correct, as there are 5 answers and 1 correct answer choice.

The \frac{4}{5} represents the chances of getting the question incorrect, as there are 5 answers and 4 incorrect answer choices.

The equation above does show the student getting two answers correct and three answers incorrect, but it only shows one possible case of doing so.

We can choose any two of the five questions to be the ones the student gets correct. Therefore, we need to multiply this equation by the number ways we can choose 2 from 5 (order doesn't matter): \binom{5}{2}=10.

Therefore, the probability the student gets two questions correct is:

\frac{1}{5}\cdot \frac{1}{5}\cdot \frac{4}{5}\cdot \frac{4}{5}\cdot \frac{4}{5}\cdot \binom{5}{2}=\frac{1}{5}\cdot \frac{1}{5}\cdot \frac{4}{5}\cdot \frac{4}{5}\cdot \frac{4}{5}\cdot 10=0.2048\approx \boxed{20.5\%}

6 0
3 years ago
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