Answer:
<em>Choice: B.</em>
Step-by-step explanation:
<u>Operations With Functions</u>
Given the functions:
![f(x)=\sqrt[3]{12x+1}+4](https://tex.z-dn.net/?f=f%28x%29%3D%5Csqrt%5B3%5D%7B12x%2B1%7D%2B4)

The function (g-f)(x) can be obtained by replacing both functions and subtracting them as follows:

![(g-f)(x)= \log(x-3)+6 - (\sqrt[3]{12x+1}+4)](https://tex.z-dn.net/?f=%28g-f%29%28x%29%3D%20%5Clog%28x-3%29%2B6%20-%20%28%5Csqrt%5B3%5D%7B12x%2B1%7D%2B4%29)
Operating:
![(g-f)(x)= \log(x-3)+6 - \sqrt[3]{12x+1}-4](https://tex.z-dn.net/?f=%28g-f%29%28x%29%3D%20%5Clog%28x-3%29%2B6%20-%20%5Csqrt%5B3%5D%7B12x%2B1%7D-4)
Joining like terms:
![\boxed{(g-f)(x)= \log(x-3) - \sqrt[3]{12x+1}+2}](https://tex.z-dn.net/?f=%5Cboxed%7B%28g-f%29%28x%29%3D%20%5Clog%28x-3%29%20-%20%5Csqrt%5B3%5D%7B12x%2B1%7D%2B2%7D)
Choice: B.
Answer:
128 degrees
Step-by-step explanation:
B = D
B = 128
Therefore, D = 128
Answer:
In AMNO, n = 92 inches, N=119° and 20=20°. Find the length of m, to the nearest 10th of an inch In AJKL, j = 9.6 inches, k = 6.4 inches and I=8.4 inches. Find the measure of K to thelaearest degree. In AQRS. q = 49 cm, 7.1 cm and S=70°. Find the area of AQRS, to the nearest 10th of a square centimeter Find all angles, 0 = 0 < 360°, that satisfy the equation below, to the nearest 10th of a degree. 25 sino-1=0 Find all angles, 0 SC <360°, that satisfy the equation below, to the nearest tenth of a degree (if necessary). 12 sin C + 6 = 5 sin ( + 6
Step-by-step explanation: