Answer:
The equation has two solutions for x:
<u>x₁ = (8 + 10i)/2</u>
<u>x₂ = (8 - 10i)/2</u>
Step-by-step explanation:
Let's use the quadratic formula for solving for x in the equation:
X^2 - 8X + 41= 0
x² - 8x + 41 = 0
Let's recall that the quadratic formula is:
x = -b +/- (√b² - 4ac)/2a
Replacing with the real values, we have:
x = 8 +/- (√-8² - 4 * 1 * 41)/2 * 1
x = 8 +/- (√64 - 164)/2
x = 8 +/- (√-100)/2
x = 8 +/- (√-1 *100)/2
Let's recall that √-1 = i
x = 8 +/- 10i/2
<u>x₁ = (8 + 10i)/2</u>
<u>x₂ = (8 - 10i)/2</u>
Answer:
x^2 - 25 ✔
Step-by-step explanation:
(x+5)(x-5)
x(x-5) +5(x-5)
x^2 - 5x + 5x - 25
x^2 - 25
The answer is 1188.
Hope it helped :)
Answer:
315
Step-by-step explanation:
wWWWwwww
wwww
lll
ll
l
ll
l
ll
ll
ll
ll
l
ll
l
lllll
ll
l
llll
ll
ll
l
l
Coming from a 6th grader but I hope this is right!
Polynomials of degree greater than 2 can have more than one max or min value. The largest possible number of minimum or maximum points is one less than the degree of the polynomial. The following examples illustrate several possibilities.
since the degree is 4
number of possible extreme values = 4 -1 = 3