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igor_vitrenko [27]
3 years ago
7

In the 2009 NFL regular season, quarterback Drew Brees of the New Orleans Saints had an average of 293 passing yards per game wi

th a
standard deviation of 74 yards. Between which two values do you expect the middle 95% of his performances to be?
Your answer:
0 0 and 515
219 and 367
O 0 and 415
145 and 441
Clear answer
Mathematics
1 answer:
Semmy [17]3 years ago
7 0

Answer:

Drew Christopher Brees (/briːz/;[1] born January 15, 1979) is a former American football quarterback who played in the National Football League (NFL) for 20 seasons.[2] A member of the New Orleans Saints for most of his career, Brees is the NFL leader in career pass completions, career completion percentage, and regular season passing yards, along with being second in career touchdown passes and career pass attempts. He also holds the record of consecutive games with a touchdown pass, breaking the feat held by Johnny Unitas for 52 years.

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Convert 1.02 kg into tonnes
antiseptic1488 [7]

Answer:

1 \: kg =1 \times  {10}^{ - 3}  \: tonnes \\ 1.02 \: kg =  \frac{1.02 \times 1 \times  {10}^{ - 3} }{1}  \\  =0.00102 \: tonnes

3 0
3 years ago
Read 2 more answers
a car rental company charges an initial fee plus a constant fee per kilometer driven this table compares a total distance driven
ollegr [7]

Answer:

$120

Step-by-step explanation:

The initial fee that was charged is the y-intercept of the equation that represents the situation given.

Using the slope-intercept equation, y = mx + b, find m and then find b, which is the initial fee.

Where, x = distance, y = price, m = slope, and b = y-intercept, which is the initial fee that was charged that we are looking for.

First, using two pairs, (105, 183) and (140, 204), find the slope (m):

m = \frac{y_2 - y_1}{x_2 - x_1} = \frac{204 - 183}{140 - 105} = \frac{21}{35} = \frac{3}{5}

m = ⅗

To find the y-intercept, b, substitute x = 105, y = 183, and m = ⅗ into y = mx + b.

183 = \frac{3}{5}(105) + b

183 = 63 + b

Subtract 63 from each side

183 - 63 = b

120 = b

The initial fee of the company is $120.

7 0
3 years ago
The first team of workers received 50 kg of cement less than the second team. for every hour of work the first team was using 15
stepladder [879]
There are 2 unknown terms in this problem 
the amount of cement the first team received is termed as 'x' hereafter 
the cement the second team received is termed as 'y'
the first team received 50 kg less, the 1st equation is as follows;

x = y - 50    after rearranging 
1) x-y = -50
for every hour 150 kg and 200 kg were used by the two teams separately 
after three hours first team used up 150*3 = 450 kg
the second team used up 200 * 3 = 600 kg
however the first team had 1.5 times as much as second team had after three hours. 
After three hours;
the amount second team had leftover was y - 600
the amount first team had leftover was x - 450
 the amount the second team had ,multiplied by 1.5 is equal to what the first team had
we can build the 2nd equation using this information

1.5 * (y-600) = x-450
1.5y - 900 = x - 450 
rearrange the equation,
 
 1.5y - x = -450 +900
2) 1.5y - x = 450 

add 1st and 2nd equations to eliminate x 
1) + 2)     (x - y = -50) + (1.5y - x = 450)
1.5y - y = 450 -50
0.5y = 400
y = 400/ 0.5
y = 800 kg
substitute y = 800 in x = y - 50
x = 800 - 50 
x = 750 kg

first team received 750 kg and second team received 800 kg


8 0
3 years ago
PLEASE HELP ASAP!!! THANK YOU! please!
andrew-mc [135]

Answer: 5. x=33, y= 33, z=114

Step-by-step explanation: the triangles and supplementary lines all add to 180, so find one of them, and use that one to find the others

5 0
3 years ago
Read 2 more answers
Determine the quadrant when the terminal side of the angle lies according to the following conditions: cos (t) < 0, csc (t) &
Bess [88]

Answer:

The angle is in the second quadrant.

Step-by-step explanation:

The cosecant of an angle is the same as the reciprocal of the sine of that angle. In other words, as long as \sin (t) \ne 0,

\displaystyle \csc t = \frac{1}{\sin t}.

Therefore, \csc(t) > 0 is equivalent to \sin (t) > 0.

Consider a unit circle centered at the origin. If the terminal side of angle t intersects the unit circle at point (x,\, y), then

  • \cos (t) = x, and
  • \sin(t) = y.

For angle t,

  • x = \cos(t) < 0, meaning that the intersection is to the left of the y-axis.
  • y = \sin(t) > 0, meaning that the intersection is above the x-axis.

In other words, this intersection is above and to the left of the origin. That corresponds to second quadrant of the cartesian plane.

6 0
3 years ago
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