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Svetllana [295]
3 years ago
13

the equation of the line / is -3y+4x=9. write the equation of a line that is parallel to the line / and passes through the point

(-12,6).
Mathematics
1 answer:
nekit [7.7K]3 years ago
4 0

Hey!

So before trying to figure out the equation of the line, lets change -3y+4x = 9 into slope-intercept form:

-3y + 4x = 9

-3y = -4x + 9

y = (4/3)x - 3

Now that you have the equation in slope-intercept form we can find the equation of the line parallel to this. One thing that we are given from this equation is the slope of the line, the slope for two parallel lines are the same. So we know that the slope of the line is 4/3. We are also given another point on the line and we can plug this point in for y and x to find the y-intercept or b:

6 = (4/3)(-12) + b

6 = -16 + b

22 = b

Now that we know b, we have both the y-intercept and the slope so our equation would be:

y = (4/3)x + 22

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Answer: C. 18.8w

Step-by-step explanation:

Since Toby exercise 14hours a week, and John exercises 20% more than Toby

John increment in number of hours compared to Tobi will be;

20/100 ×14 = 2.8hrs

This shows John exercises 2.8hrs more than Tobi. Total number of hours exercised by John will become;

14+2.8 = 16.8hrs

Since Jenny exercises two more hours than John, Total number of hours exercised by Jenny will be;

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If Jenny exercise 18.8hrs in a week, it means she will exercise 18.8×w/1 in w weeks which gives 18.8w weeks.

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Find angle D if angle B = 50
Mariana [72]
<h3>Answer:  80 degrees</h3>

============================================================

Explanation:

I'm assuming that segments AD and CD are tangents to the circle.

We'll need to add a point E at the center of the circle. Inscribed angle ABC subtends the minor arc AC, and this minor arc has the central angle AEC.

By the inscribed angle theorem, inscribed angle ABC = 50 doubles to 2*50 = 100 which is the measure of arc AC and also central angle AEC.

----------------------------

Focus on quadrilateral DAEC. In other words, ignore point B and any segments connected to this point.

Since AD and CD are tangents, this makes the radii EA and EC to be perpendicular to the tangent segments. So angles A and C are 90 degrees each for quadrilateral DAEC.

We just found angle AEC = 100 at the conclusion of the last section. So this is angle E of quadrilateral DAEC.

---------------------------

Here's what we have so far for quadrilateral DAEC

  • angle A = 90
  • angle E = 100
  • angle C = 90
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Now we'll use the idea that all four angles of any quadrilateral always add to 360 degrees

A+E+C+D = 360

90+100+90+D = 360

D+280 = 360

D = 360-280

D = 80

Or a shortcut you can take is to realize that angles E and D are supplementary

E+D = 180

100+D = 180

D = 180-100

D = 80

This only works if AD and CD are tangents.

Side note: you can use the hypotenuse leg (HL) theorem to prove that triangle EAD is congruent to triangle ECD; consequently it means that AD = CD.

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