Not necessarily.

and

may be linearly dependent, so that their span forms a subspace of

that does not contain every vector in

.
For example, we could have

and

. Any vector

of the form

, where

, is impossible to obtain as a linear combination of these

and

, since

unless

and

.
Included in your weekly circular should be free coupons, so coupons are free (disregarding the price you have to pay to live around the area)
if you want to know how much discount the coupon give you then
4.5*3/10=1.35
takes off $1.35
proportion method
30/100=x/4.5
3/10=x/4.5
cross multiply or ties both sides by 10*4.5
3*4.5=10x
13.5=10x
divide both sides by 10
1.35=x
discount of $1.35 (coupon saves you $1.35)
D'ou know the area of a circle?
Answer:
okay so it would be 2 or 1.5 i dont know if you want it whole number but i will explain
if the number is 5 or more like 5.1 or even 5 you round up
if the number is under 5 like 4,3,2,1 your round down
Step-by-step explanation:
Answer:
5.3
Step-by-step explanation:
You use the Pythagoras theorem which is a^2+b^2=c^2.
Since you're solving for a side length that's not the hypotenuse you will manipulate the equation to c^2-a^2=b^2. From here you just plug in numbers.
8^2 - 6^2 = b^2
64 - 36 = b^2
b = sqrt(28)
b = 5.2915.... = 5.3