Answer:
6 mm and 9 mm are the dimensions of the piece of plastic.
Step-by-step explanation:
Keep in mind the formulas for the area and perimeter of a rectangle:
A = lw
P = 2 (l + w)
List the factors of 54:
1, 2, 3, 6, 9, 18, 27, 54
POSSIBLE DIMENSIONS of the piece of plastic:
1 mm and 54 mm:
Area - 54 mm^2
Perimeter - 110 mm
2 mm and 27 mm
Area - 54 mm^2
Perimeter - 58 mm
3 mm and 18 mm
Area - 54 mm^2
Perimeter - 42 mm
6 mm and 9 mm
Area - 54 mm^2
Perimeter - 30 mm
The rectangular piece of plastic with the dimensions 6mm and 9 mm corresponds with the area and perimeter of the piece of plastic mentioned. So these are the correct dimensions.
Hope this helps!
Y=1 because no matter the x value y will be 1
<h3><u>Answer</u> :</h3>
![\bigstar\:\boxed{\bf{\purple{x^{\frac{m}{n}}}=\orange{(\sqrt[n]{x})^m}}}](https://tex.z-dn.net/?f=%5Cbigstar%5C%3A%5Cboxed%7B%5Cbf%7B%5Cpurple%7Bx%5E%7B%5Cfrac%7Bm%7D%7Bn%7D%7D%7D%3D%5Corange%7B%28%5Csqrt%5Bn%5D%7Bx%7D%29%5Em%7D%7D%7D)
Let's solve !
![:\implies\sf\:(\sqrt[2]{25})^3](https://tex.z-dn.net/?f=%3A%5Cimplies%5Csf%5C%3A%28%5Csqrt%5B2%5D%7B25%7D%29%5E3)
<u>Hence, Oprion-D is correct</u> !
Answer:
Step-by-step explanation:
y![f(x)^{-1} = inverse\\f(x)=y \\y = 1/(x^{3} \\Inverse: y=x ------------> x = 1/y^{3}\\y^{3} - \frac{1}{x} = 0\\y^{3} = \frac{1}{x}\\y = \sqrt[3]{\frac{1}{x}} \\y = \frac{\sqrt[3]{1} }{\sqrt[3]{x}} \\y = \frac{1}{\sqrt[3]{x}}](https://tex.z-dn.net/?f=f%28x%29%5E%7B-1%7D%20%20%3D%20inverse%5C%5Cf%28x%29%3Dy%20%5C%5Cy%20%3D%201%2F%28x%5E%7B3%7D%20%5C%5CInverse%3A%20y%3Dx%20------------%3E%20x%20%3D%201%2Fy%5E%7B3%7D%5C%5Cy%5E%7B3%7D%20-%20%5Cfrac%7B1%7D%7Bx%7D%20%3D%200%5C%5Cy%5E%7B3%7D%20%3D%20%5Cfrac%7B1%7D%7Bx%7D%5C%5Cy%20%3D%20%5Csqrt%5B3%5D%7B%5Cfrac%7B1%7D%7Bx%7D%7D%20%5C%5Cy%20%3D%20%5Cfrac%7B%5Csqrt%5B3%5D%7B1%7D%20%7D%7B%5Csqrt%5B3%5D%7Bx%7D%7D%20%5C%5Cy%20%3D%20%5Cfrac%7B1%7D%7B%5Csqrt%5B3%5D%7Bx%7D%7D)
