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CaHeK987 [17]
3 years ago
5

Which of the following happens when 21.63 is multiplied by 103?

Mathematics
1 answer:
anastassius [24]3 years ago
7 0
Answer: A
Because it is

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Meiling needs 5 dollars 35 cents to buy a ticket to a show. In her wallet, she finds 2 dollar bills, 11 dimes, and 5 pennies. Ho
Llana [10]

Answer:

no she needs $2.20 more

Step-by-step explanation:

2+ 1.10+.05= $3.15

$5.35 - $3.15 = the answer

5 0
3 years ago
What is the discriminate?
weqwewe [10]
So it’s basically asking for the difference
4 0
2 years ago
Find the value of x. Then find the measure of each labeled angle. x = 37.5; the labeled angles are 77.5º and 102.5º. x = 37.5; t
Ne4ueva [31]

Answer:

x = 25; both labeled angles are 65º

Step-by-step explanation:

To find the value of x, recall that the angles formed by two parallel lines on the same line are equal if they correspond to each other.

In the figure given above, we have two parallel line given. The angle formed by each parallel line is corresponding to the other. Therefore, both angles formed are equal.

Thus,

(3x - 10)° = (x + 40)°

Solve for x

3x - 10 = x + 40

Subtract x from both sides

3x - 10 - x = x + 40 - x

3x - x - 10 = x - x + 40

2x - 10 = 40

Add 10 to both sides

2x - 10 + 10 = 40 + 10

2x = 50

Divide both sides by 2

2x/2 = 50/2

x = 25

*Plug in the value of x to find the measure of each labelled angles:

(3x - 10)° = 3(25) - 10 = 75 - 10 = 65°

(x + 40)° = 25 + 40 = 65°

3 0
3 years ago
A fish tank holds 95 gallons of water but is losing 4 gallons per day. A second fish tank contains 40 gallons but has 5 gallons
Bingel [31]
After Day 7 the Second would have more water.
8 0
2 years ago
A company wants to establish that the mean life of its batteries, when used in a wireless mouse, is over 183 days. The data will
enyata [817]

Answer:

a) Null and alternative hypotheses are:

H_{0}: mu=183 days

H_{a}: mu>183 days

b) If the true mean is 190 days, Type II error can be made.

Step-by-step explanation:

Let mu be the mean life of the batteries of the company when it is used in a wireless mouse

Null and alternative hypotheses are:

H_{0}: mu=183 days

H_{a}: mu>183 days

Type II error happens if we fail to reject the null hypothesis, when actually the alternative hypothesis is true.

That is if we conclude that mean life of the batteries of the company when it is used in a wireless mouse is at most 183 days, but actually mean life is 190 hours, we make a Type II error.

4 0
3 years ago
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