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3 years ago

11

Consider the graph of the expotential function y= 3(2)^x

1 answer:

victus00 [196]3 years ago

8 0

Answer:

<h2>y-intercept = 3</h2><h2>x-intercept - not exist</h2><h2>the graph is increasing</h2>

Step-by-step explanation:

The exponential function:

$f(x)=b(a)^x$

has y-intercept for x = 0

hasn't x-intercept

if a > 1, then is increasing

if 0 < a < 1, then is decreasing

We have

$y=3(2)^x$

a = 2 >1 - increasing

for x = 0:

$y=3(2)^0=3(1)=3$

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2 years ago

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Please help!!! The sum of three consecutive integers is 9.

Travka [436]

Answer:

2

Step-by-step explanation:

because they're consecutive, each integer has to come right after the one before it.

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2 years ago

Which two numbers add up to -19 and multiply to make 35

iris [78.8K]

x+y = -19
x*y = 35

x=-19-y
(-19-y)y = 35
y^2 +19y +35 = 0
y = -2.066965626
therefore x=35/y = -16.93303437

4 0

3 years ago

Find the derivative of f(x) = 12x^2 + 8x at x = 9.

zvonat [6]

Answer:

224

Step-by-step explanation:

We will need the following rules for derivative:

$(f+g)'=f'+g'$ Sum rule.

$(cf)'=cf'$ Constant multiple rule.

$(x^n)'=nx^{n-1}$ Power rule.

$(x)'=1$ Slope of y=x is 1.

$f(x)=12x^2+8x$

$f'(x)=(12x^2+8x)'$

$f'(x)=(12x^2)'+(8x)'$ by sum rule.

$f'(x)=12(x^2)+8(x)'$ by constant multiple rule.

$f'(x)=12(2x)+8(1)$ by power rule.

$f'(x)=24x+8$

Now we need to find the derivative function evaluated at x=9.

$f'(9)=24(9)+8$

$f'(9)=216+8$

$f'(9)=224$

In case you wanted to use the formal definition of derivative:

$f'(x)=\lim_{h \rightarrow 0} \frac{f(x+h)-f(x)}{h}$

Or the formal definition evaluated at x=a:

$f'(a)=\lim_{h \rightarrow 0} \frac{f(a+h)-f(a)}{h}$

Let's use that a=9.

$f'(9)=\lim_{h \rightarrow 0} \frac{f(9+h)-f(9)}{h}$

We need to find f(9+h) and f(9):

$f(9+h)=12(9+h)^2+8(9+h)$

$f(9+h)=12(9+h)(9+h)+72+8h$

$f(9+h)=12(81+18h+h^2)+72+8h$

(used foil or the formula (x+a)(x+a)=x^2+2ax+a^2)

$f(9+h)=972+216h+12h^2+72+8h$

Combine like terms:

$f(9+h)=1044+224h+12h^2$

$f(9)=12(9)^2+8(9)$

$f(9)=12(81)+72$

$f(9)=972+72$

$f(9)=1044$

Ok now back to our definition:

$f'(9)=\lim_{h \rightarrow 0} \frac{f(9+h)-f(9)}{h}$

$f'(9)=\lim_{h \rightarrow 0} \frac{1044+224h+12h^2-1044}{h}$

Simplify by doing 1044-1044:

$f'(9)=\lim_{h \rightarrow 0} \frac{224h+12h^2}{h}$

Each term has a factor of h so divide top and bottom by h:

$f'(9)=\lim_{h \rightarrow 0} \frac{224+12h}{1}$

$f'(9)=\lim_{h \rightarrow 0}(224+12h)$

$f'(9)=224+12(0)$

$f'(9)=224+0$

$f'(9)=224$

8 0

3 years ago

marin [14]

Answer

32 dollars

Explanation

4*8

8 0

2 years ago