Consider the graph of the expotential function y= 3(2)^x

Commemorative coins come in packs of 15,while coin holders come in packs of 25. What are the least numbers of packs you should b

kozerog [31]

The least common multiple of 25 and 15 is 75. You'd do _ x 25 = 75 and _ x 15 = 75. The answer would be 3 and 5, so 5 packs of coins and 3 packs of coin holders.

7 0

3 years ago

Read 2 more answers

Graph the function. <br><br> g(x) = 1/2 • 2^x

Trava [24]

g(x) = 1/2 . 2^x = x=3 , y=1

5 0

3 years ago

Last year, a comprehensive report stated that 28% of businesses in the northeast of Ohio were considered highly profitable. This

Alik [6]

Answer:

$z=\frac{0.38 -0.28}{\sqrt{\frac{0.28(1-0.28)}{50}}}=1.575$

$p_v =2*P(z>1.575)=0.115$

So the p value obtained was a very high value and using the significance level given $\alpha=0.01$ we have $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the proportion of businesses were highly profitable is not significantly different from 0.28 or 28%.

Step-by-step explanation:

Data given and notation

n=50 represent the random sample taken

X=19 represent the businesses were highly profitable

$\hat p=\frac{19}{50}=0.38$ estimated proportion of businesses were highly profitable

$p_o=0.28$ is the value that we want to test

$\alpha=0.05$ represent the significance level

Confidence=95% or 0.95

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that the true proportion of businesses were highly profitable is different from 0.28 or no, the system of hypothesis is.:

Null hypothesis: $p=0.28$

Alternative hypothesis: $p \neq 0.28$

When we conduct a proportion test we need to use the z statistic, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

Calculate the statistic

Since we have all the info required we can replace in formula (1) like this:

$z=\frac{0.38 -0.28}{\sqrt{\frac{0.28(1-0.28)}{50}}}=1.575$

Statistical decision

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The significance level provided $\alpha=0.01$ . The next step would be calculate the p value for this test.

Since is a bilateral test the p value would be:

$p_v =2*P(z>1.575)=0.115$

So the p value obtained was a very high value and using the significance level given $\alpha=0.01$ we have $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the proportion of businesses were highly profitable is not significantly different from 0.28 or 28%.

4 0

4 years ago

Will give brainliest for *BEST* answer!

Nataliya [291]

Use substitution and substitute y into the other equation. One of the equations already gives you y in terms of x, so use that and substitute it into the other equation. y = 3x - 4

Plug into the other equation: -3y = -9x + 12
-3(3x-4) = -9x + 12
-9x + 12 = -9x + 12
This is an identity. So that means that any value of x makes this equation true. So B.

8 0

4 years ago

What is the smallest number which when decreased by 8 is divisible by 21, 27, 33, and 55?.

evablogger [386]

The required number which when decreased by 8 is divisible by 21, 27, 33, and 55 is 10403.

We need to find the smallest number which when decreased by 8 is divisible by 21, 27, 33, and 55.

The least common multiple is also known as LCM (or) the lowest common multiple in math. The least common multiple of two or more numbers is the smallest number among all common multiples of the given numbers.

We find the LCM of 21, 27, 33, and 55.

3 | 21 27 33 55

3 | 7 9 11 55

3 | 7 3 11 55

7 | 7 1 11 55

5 | 1 1 11 55

11 | 1 1 11 11

| 1 1 1 1

When decreased by 8, we have to add 8 in the LCM of the numbers.

That is 10395+8=10403

Therefore, the required number when decreased by 8 is divisible by 21, 27, 33, and 55 is 10403.

To learn more about the LCM of numbers visit:

brainly.com/question/10942748.

#SPJ4

8 0

2 years ago