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adell [148]
3 years ago
11

Consider the graph of the expotential function y= 3(2)^x

Mathematics
1 answer:
victus00 [196]3 years ago
8 0

Answer:

<h2>y-intercept = 3</h2><h2>x-intercept - not exist</h2><h2>the graph is increasing</h2>

Step-by-step explanation:

The exponential function:

f(x)=b(a)^x

has y-intercept for x = 0

hasn't x-intercept

if a > 1, then is increasing

if 0 < a < 1, then is decreasing

We have

y=3(2)^x

a = 2 >1 - increasing

for x = 0:

y=3(2)^0=3(1)=3

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Step-by-step explanation:

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Please help!!! The sum of three consecutive integers is 9.​
Travka [436]

Answer:

2

Step-by-step explanation:

because they're consecutive, each integer has to come right after the one before it.

if 1st integer is 1, the 2nd should be 2, and the 3rd should be 3.

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hopefully that works

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2 years ago
Which two numbers add up to -19 and multiply to make 35
iris [78.8K]

x+y = -19
x*y  = 35

x=-19-y
(-19-y)y = 35
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4 0
3 years ago
Find the derivative of f(x) = 12x^2 + 8x at x = 9.
zvonat [6]

Answer:

224

Step-by-step explanation:

We will need the following rules for derivative:

(f+g)'=f'+g' Sum rule.

(cf)'=cf' Constant multiple rule.

(x^n)'=nx^{n-1} Power rule.

(x)'=1 Slope of y=x is 1.

f(x)=12x^2+8x

f'(x)=(12x^2+8x)'

f'(x)=(12x^2)'+(8x)' by sum rule.

f'(x)=12(x^2)+8(x)' by constant multiple rule.

f'(x)=12(2x)+8(1) by power rule.

f'(x)=24x+8

Now we need to find the derivative function evaluated at x=9.

f'(9)=24(9)+8

f'(9)=216+8

f'(9)=224

In case you wanted to use the formal definition of derivative:

f'(x)=\lim_{h \rightarrow 0} \frac{f(x+h)-f(x)}{h}

Or the formal definition evaluated at x=a:

f'(a)=\lim_{h \rightarrow 0} \frac{f(a+h)-f(a)}{h}

Let's use that a=9.

f'(9)=\lim_{h \rightarrow 0} \frac{f(9+h)-f(9)}{h}

We need to find f(9+h) and f(9):

f(9+h)=12(9+h)^2+8(9+h)

f(9+h)=12(9+h)(9+h)+72+8h

f(9+h)=12(81+18h+h^2)+72+8h

(used foil or the formula  (x+a)(x+a)=x^2+2ax+a^2)

f(9+h)=972+216h+12h^2+72+8h

Combine like terms:

f(9+h)=1044+224h+12h^2

f(9)=12(9)^2+8(9)

f(9)=12(81)+72

f(9)=972+72

f(9)=1044

Ok now back to our definition:

f'(9)=\lim_{h \rightarrow 0} \frac{f(9+h)-f(9)}{h}

f'(9)=\lim_{h \rightarrow 0} \frac{1044+224h+12h^2-1044}{h}

Simplify by doing 1044-1044:

f'(9)=\lim_{h \rightarrow 0} \frac{224h+12h^2}{h}

Each term has a factor of h so divide top and bottom by h:

f'(9)=\lim_{h \rightarrow 0} \frac{224+12h}{1}

f'(9)=\lim_{h \rightarrow 0}(224+12h)

f'(9)=224+12(0)

f'(9)=224+0

f'(9)=224

8 0
3 years ago
Question 10
marin [14]
Answer

32 dollars

Explanation

4*8
8 0
2 years ago
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