Answer:
4/3
Step-by-step explanation:
A proportional relationship is a relationship that crosses through the origin or (0,0). This means the slope of the line can be found by subtracting the points (12,16) and (0,0) in the slope formula.

So the slope is 4/3 and must be the value between any two points on the line.
This means the function moves from (0,0) to (1, 4/3).



→ Substitute cos 2x and sin 2x by their expressions

→ Subtract both sides by sin x

→ Take sin x as a common factor in the right side

From the graph, the equation has 4 solutions, the intersection points between the 2 graphs
Answer:
x - 2, if x > 5
Step-by-step explanation:
The vertical lines either side of the expression mean absolute value.
The absolute value of a number is its <u>positive numerical value</u>.
if x > 5 then as 5 > 2, the values inside the vertical lines will always be positive. Therefore, we can disregard the absolute value.
Therefore:
x - 2, if x > 5
To find the range (output values) of the expression, substitute x = 5 into the expression:
⇒ 5 - 2 = 3
Therefore, |x - 2| > 3, if x > 5
Answer:
you are saying it wrong its 1\8 and 3\3
Step-by-step explanation: