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3 years ago

2. What is the product of 4 2/3 and 11 1/4?

Mathematics

1 answer:

Lerok [7]3 years ago

3 0

$4 \frac{3}{4} ~*~ 11\frac{1}{4} = \frac{14}{3} ~*~ \frac{45}{4} = \frac{630}{12}=52 \frac{6}{12} =[52 \frac{1}{2} ]$

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How do you estimate 1,374×6

san4es73 [151]

The best estimate for 1,374 is 1,400 and the best estimate for 6 is 10. This is because anything that is 5 and above you change it. Example: 16 the best estimate for 16 is 20 because 6 is above 5. And when a number is 4 and below you change the number below. Example: 12 the best estimate for 12 is 10 because 2 is below 4. And when the number is perfect like 10, you can keep the number the same. Example:10,20,30,40,50,60etc.
Hope this Helped! :)

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3 years ago

At the airport, there is a moving walkaway 500 meters long, which moves at a speed of 4 km/hour. Aditya and Ravi step on the wal

Nutka1998 [239]

Answer:

He is approximately 166.6 m ahead of Ravi.

If it's right please mark BRAINLIEST

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2 years ago

Read 2 more answers

4/3x + 1/6x = 36 (solve for x please help I have no idea what it is!!!!!!!

ElenaW [278]

Answer:

x = 24

Step-by-step explanation:

$\frac{4}{3}$ x + $\frac{1}{6}$ x = 36

Make the denominator the same by multiplying the first fraction by 2 to make both denominators 6.

$\frac{8}{6}$ x + $\frac{1}{6}$ x = 36

Now we can calculate the numerators and keep the denominators the same.

$\frac{9}{6}$ x = 36

Find x.

$\frac{6}{6}$ x = $\frac{6}{9}$ × 36

x = 24

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2 years ago

Malik’s weekly pay varies directly to the number of hours he works as a lifeguard. His weekly pay is $246.50 when he works 17 ho

mash [69]

Answer:

Step-by-step explanation:

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3 years ago

As a follow-up to a report on gas consumption, a consumer group conducted a study of SUV owners to estimate the mean mileage f

kondor19780726 [428]

Answer:

The 95% confidence interval estimate for the mean highway mileage for SUVs is (18.29mpg, 20.91mpg).

Step-by-step explanation:

Our sample size is 96.

The first step to solve this problem is finding our degrees of freedom, that is, the sample size subtracted by 1. So

$df = 96-1 = 95$

Then, we need to subtract one by the confidence level $\alpha$ and divide by 2. So:

$\frac{1-0.95}{2} = \frac{0.05}{2} = 0.025$

Now, we need our answers from both steps above to find a value T in the t-distribution table. So, with 95 and 0.025 in the t-distribution table, we have $T = 1.9855$ .

Now, we find the standard deviation of the sample. This is the division of the standard deviation by the square root of the sample size. So

$s = \frac{5.6}{\sqrt{96}} = 0.57$

Now, we multiply T and s

$M = T*s = 1.9855*0.57 = 1.31$

For the lower end of the interval, we subtract the mean by M. So $19.6 - 1.31 = 18.29$

For the upper end of the interval, we add the mean to M. So $19.6 + 1.31 = 20.91$

The 95% confidence interval estimate for the mean highway mileage for SUVs is (18.29mpg, 20.91mpg).

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3 years ago