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melamori03 [73]
3 years ago
10

2. What is the product of 4 2/3 and 11 1/4?

Mathematics
1 answer:
Lerok [7]3 years ago
3 0
4 \frac{3}{4} ~*~ 11\frac{1}{4} =  \frac{14}{3} ~*~ \frac{45}{4} =  \frac{630}{12}=52 \frac{6}{12}  =[52 \frac{1}{2} ]
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What type of trig has the equation ax+bx+c=0 ?
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The diameter of circles A,C and E are 32 cm, 24cm and 14 cm respectively
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Answer:

AG = 4

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Step-by-step explanation:

<u><em>The complete question is</em></u>

The diameters of circles A, C and E are 32 cm, 24 cm and 14 cm respectively.

Which of the following statements are true? Select all that apply.

•AG = 4

•GC = 10

•AH = 21

•EC = 12

•EH = 5

•CH = 5

•HE = 7

The picture of the question in the attached figure

<u><em>Verify each statement</em></u>

1) AG = 4

we know that

AG=AC-GC

AC=32\2=16\ cm ----> radius of circle A

GC=24/2=12\ cm ----> radius of circle C

substitute

AG=16-12=4\ cm

therefore

The statement is true

2) GC = 10

we know that

GC=24/2=12\ cm ----> radius of circle C

therefore

The statement is false

3) AH = 21

we know that

AH=AC+CH

we have

AC=16\ cm ----> radius of circle A

CH=CE-HE

CE=12\ cm ----> radius of circle C

HE=14/2=7\ cm ----> radius of circle E

so

CH=12-7=5\ cm

AH=16+5=21\ cm

therefore

The statement is true

4) EC = 12

we know that

EC=24/2=12\ cm ----> radius of circle C

therefore

The statement is true

5) EH = 5

we know that

EH=14/2=7\ cm ----> radius of circle E

therefore

The statement is false

6) CH = 5

we know that

CH=CE-HE

CE=12\ cm ----> radius of circle C

HE=14/2=7\ cm ----> radius of circle E

so

CH=12-7=5\ cm

therefore

The statement is true

7) HE = 7

we know that

HE=14/2=7\ cm ----> radius of circle E

therefore

The statement is true

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