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Tresset [83]
3 years ago
6

Tres por un número que es agregado a otro numero es 18. El doble del primer número menos el otro numero es 12. Encuentra los num

ero
Mathematics
1 answer:
andre [41]3 years ago
5 0
Creo que la respusta es 6 porque 3 multiplicado por 6 es 18 y 6 multiplicado por 2 es 12.18 menos 12 es 6.
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Use the graph to the right to write an equation of the line. What is the equation?​
Bingel [31]

Answer:

y = 1/4 x - 2

Step-by-step explanation:

To write the equation of a line, find from the line the slope and y-intercept. The y-intercept is where the line crosses the y-axis which here is at point (0,-2).

The slope of the line is found by writing a ratio between the vertical distance and the horizontal distance between points.

Slope is 1/4.

Substitute m = 1/4 and b = -2 into the slope intercept form y = mx + b.

y = 1/4 x - 2

5 0
3 years ago
Which expressions are equivalent to the one below? Check all that apply.
Aleksandr [31]

Answer:

D

Step-by-step explanation:

(5·5)*x = 25*x =25^x

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5 0
3 years ago
Can SOMEONE PLEASE HELP ME WILL GIVE 30 POINTS AND BRAINLIEST!!!!!
earnstyle [38]

Answer:

Hope i helped :)

Step-by-step explanation:

8) T-V =24

24 -6 =18

2x-18 =18

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x= 0/2

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9)

*LMK

*L-K=x+3

*L-M=6x-10

*M-K= 3x-3

L-M + M-K = 6x -10 + 3x -3 = 9x -13

10 and 11)

Both lines are horizontal

both lines consist of intervals due to having 2 points on one line making it a distance between 2 points.

they are also concurrent lines because more then 3 lines pass through one point

they are also intersecting lines because they cross over each other

6 0
3 years ago
Read 2 more answers
Please help me....<br> (45 points!!!)
maksim [4K]

I think the equation you would use is y=26x+0.003.

8 0
3 years ago
I need to rewrite d and h without the use of fractional or negative exponents by using radicals, how I do that???
jolli1 [7]

Answer:

The pencil marks on your page show you exactly how to do that.

Step-by-step explanation:

Take advantage of two rules of exponents:

\sqrt[n]{x}=x^{\frac{1}{n}}\\\\x^{-n}=\dfrac{1}{x^{n}}

(d)\quad x^{\frac{-1}{5}}=\dfrac{1}{x^{\frac{1}{5}}}=\dfrac{1}{\sqrt[5]{x}}\\\\(h)\quad x^{\frac{-2}{11}}=\dfrac{1}{x^{\frac{2}{11}}}=\dfrac{1}{\sqrt[11]{x^{2}}}

3 0
3 years ago
Read 2 more answers
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