3 years ago

Find all points on the y-axis that are a distance 6 from p(4, 7).

1 answer:

8 0

$\sqrt{16 + {(7 - y)}^{2} } = 6 \\ 16 + {(7 - y)}^{2} = 36 \\ {(7 - y)}^{2} = 20$
$7 - y = \sqrt{20} > > y = 7 - \sqrt{20} \\ 7 - y = - \sqrt{20} > > y = 7 + \sqrt{20}$

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