The calculations for 2, 4, 8 year can be derived as follows,
For simple interest:
S.I = 
P= principle
T= Time
R= Rate
For 2 year;
S.I =
= $224
Amount = $2224
For 4 year;
S.I =
= $448
Amount = $2448
For 8 year;
S.I =
= $896
Amount = $2896
You define a function f(x) which gives the cost of buying x packages of cookies. You are asked for the domain of the function. That is, what values can x take on? x is the number of packages bought.
It makes no sense to buy a negative number of packages. It also makes no sense to buy 1/2 a package or 3/4 of a package as the store won’t sell you a fraction of a package. Try going to the store and buying half a package of oreo cookies. I doubt you’ll get very far :)
So it makes sense to buy 0, 1, 2, 3, 4, ... boxes of cookies. These are whole numbers. So the domain is the set of whole numbers. You could also write the domain like this {0, 1, 2, 3, ...} making sure to use the curly brackets as those denote a set.
9514 1404 393
Answer:
A. no solution
B. unique solution: (x, y) = (0, 0)
Step-by-step explanation:
For these problems, you can subtract the second equation from the first to get something of the form ...
0 = (expression)
The solution of that will tell you the answer.
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A. (2x +3y) -(2x +3y) = (4) -(9)
0 = -5 . . . . . . . . no values of x or y will make this true: NO SOLUTION
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B. (y) -(y) = (6x) -(x)
0 = 5x
0 = x . . . . . . divide by the coefficient of x.
y = x = 0
The unique solution is (x, y) = (0, 0).
A butterfly can fly 82 feet in 4 seconds.
Distance traveled by butterfly = 82 feet.
Time taken by butterfly =4 seconds
Speed = distance /time
Speed of butterfly = 82/4 = 20.5 feet/second
A dragonfly can fly 50 feet in 2 seconds.
Distance traveled by dragonfly =50 feet.
Time taken by dragonfly =2 seconds.
Speed of dragonfly = 50/2 = 25 feet/second
So dragonfly can fly faster than the butterfly.
Difference in speed = speed of dragonfly - speed of butterfly = 25-20.5 = 4.5
So The dragonfly is 4.5 feet per second faster than butterfly.
Answer: B) The dragonfly is 4.5 feet per second faster.