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KIM [24]
2 years ago
11

Are triangles congruent if three pairs of corresponding sides are congruent? Pls help me.

Mathematics
2 answers:
Leto [7]2 years ago
7 0

Answer:

to my knowledge yes they are

Step-by-step explanation:

earnstyle [38]2 years ago
6 0

Answer:

if triangles are congruent if three pairs of corresponding sides are

congruent.to made a congruent triangle

following axiom need to fulfilled.

  • A.S.A AXIOM
  • S.S.S. AXIOM
  • S.A.S. AXIOM
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A number is chosen at random from 1 to 25. Find the probability of selecting an even number that is greater than 13.
mamaluj [8]

Answer:

14 16,18,20 22,24

so, 6 out of 24

6/24 simplifies to 1/4

6 0
3 years ago
Ernie bought a new DVD that cost $12 before tax. Tax on the DVD is 8.25%. What is the total cost of the DVD including tax?
hodyreva [135]

After tax it will cost $12.99.

7 0
3 years ago
I don't think this is correct plz check me
Readme [11.4K]

Answer:

The answer is the first one

Step-by-step explanation:

The cost of an adult ticket is $15

The price of an adult ticket is 1/2 the price of a student ticket plus $8

x is the cost of a student ticket, so

1/2(x) + $8 = $15

8 0
3 years ago
An electric current, I, in amps, is given by I=cos(wt)+√8sin(wt), where w≠0 is a constant. What are the maximum and minimum valu
exis [7]
Take the derivative with respect to t
- w \sin(wt) + \sqrt{8} w cos(wt)
the maximum and minimum values occur when the tangent line is zero so we set the derivative to zero
0 = -w \sin(wt) + \sqrt{8} w cos(wt)
divide by w
0 =- \sin(wt) + \sqrt{8} cos(wt)
we add sin(wt) to both sides

\sin(wt)= \sqrt{8} cos(wt)
divide both sides by cos(wt)
\frac{sin(wt)}{cos(wt)}= \sqrt{8}   \\  \\ arctan(tan(wt))=arctan( \sqrt{8} ) \\  \\ wt=arctan(2 \sqrt{2)} OR\\ wt=arctan( { \frac{1}{ \sqrt{2} } )
(wt)=2(n*pi-arctan(2^0.5))
(wt)=2(n*pi+arctan(2^-0.5))
where n is an integer
the absolute max and min will be

I=cos(2n \pi -2arctan( \sqrt{2} ))
since 2npi is just the period of cos
cos(2arctan( \sqrt{2} ))= \frac{-1}{3} 

substituting our second soultion we get
I=cos(2n \pi +2arctan( \frac{1}{ \sqrt{2} } ))
since 2npi is the period
I=cos(2arctan( \frac{1}{ \sqrt{2}} ))= \frac{1}{3}
so the maximum value =\frac{1}{3}
minimum value =- \frac{1}{3}


4 0
3 years ago
Please... time is almost up somebody?
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