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2 years ago

Write the pair of fractions as a pair of fractions with a common denominator one fourth and two thirds

1 answer:

6 0

So a common denominator of 1/2 and 2/3 is 6 (sometimes the best thing to do is multiply the two denominators that are liitle numbers lol and bam that's a common denominator)
this means that (1*3) / (2*3) and (2*2) / (3*2) to get to the common denominator
the fractions become 3/6 and 4/6

Hope this helps ;)

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Justify Reasoning Determine whether 3x + 12 + x is equivalent to 4(3 + x). Use properties of operations to justify your answer.

Orlov [11]

For 3x + 12 + x, do like terms:
4x + 12
For 4(3 + x), multiply
12 + 4x
They are both the same, just written in different ways. One is adding like terms and the other is multiplying with parentheses. Even though it may be switched around, it is still the same.

Hope this helps :)

4 0

2 years ago

In a class of p students, the average (arithmetic mean) of the test scores is 70. in another class of n students, the average of

lys-0071 [83]

First case:

average of test score =70

number of students =p

total score of 'p' students = ( average of test score)*( number of students)

total score of 'p' students =70p

Second case:

average of test score =92

number of students =n

total score of 'n' students = ( average of test score)*( number of students)

total score of 'n' students =92n

total number of students = p+n

total average score =86

so, total score =86(p+n)

total score = total score of 'p' students +total score of 'n' students

$86(p+n)=70p+92n$

now, we can simplify it

$86p+86n=70p+92n$

$86p-70p=92n-86n$

$16p=6n$

now, we can find p/n

$\frac{p}{n}= \frac{6}{16}$

$\frac{p}{n}= \frac{3}{8}$ ................Answer

5 0

2 years ago

the volume v of a right circular cylinder of radius r and heigh h is V = pi r^2 h 1. how is dV/dt related to dr/dt if h is const

laiz [17]

In general, the volume

$V=\pi r^2h$

has total derivative

$\dfrac{\mathrm dV}{\mathrm dt}=\pi\left(2rh\dfrac{\mathrm dr}{\mathrm dt}+r^2\dfrac{\mathrm dh}{\mathrm dt}\right)$

If the cylinder's height is kept constant, then $\dfrac{\mathrm dh}{\mathrm dt}=0$ and we have

$\dfrac{\mathrm dV}{\mathrm dt}=2\pi rh\dfrac{\mathrm dt}{\mathrm dt}$

which is to say, $\dfrac{\mathrm dV}{\mathrm dt}$ and $\dfrac{\mathrm dr}{\mathrm dt}$ are directly proportional by a factor equivalent to the lateral surface area of the cylinder ( $2\pi r h$ ).

Meanwhile, if the cylinder's radius is kept fixed, then

$\dfrac{\mathrm dV}{\mathrm dt}=\pi r^2\dfrac{\mathrm dh}{\mathrm dt}$

since $\dfrac{\mathrm dr}{\mathrm dt}=0$ . In other words, $\dfrac{\mathrm dV}{\mathrm dt}$ and $\dfrac{\mathrm dh}{\mathrm dt}$ are directly proportional by a factor of the surface area of the cylinder's circular face ( $\pi r^2$ ).

Finally, the general case ( $r$ and $h$ not constant), you can see from the total derivative that $\dfrac{\mathrm dV}{\mathrm dt}$ is affected by both $\dfrac{\mathrm dh}{\mathrm dt}$ and $\dfrac{\mathrm dr}{\mathrm dt}$ in combination.

8 0

2 years ago

Please help im the worst at algebra 2

nevsk [136]

SORRY ITS AO HARD

JUST ANSWER THAT

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6 0

2 years ago

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What is -3.45 minus positive 2.2

Vanyuwa [196]