We can use the Pythagorean theorem to solve for the perimeter of the kite.
a² + b² = c²
3² + 4² = UV²
9 + 16 = UV²
25 = UV²
√25 = √UV²
5 = UV
In the kite, adjacent sides are the same so UV = VW
3² + 9² = UX²
9 + 81 = UX²
90 = UX²
√90 = √UX²
9.49 ≈ UX or 3√10 ≈ UX
Now, add to find the perimeter.
5 + 5 + 9.49 + 9.49 or 5 + 5 + 3√10 + 3√10
28.98 or 10 + 6√10
Therefore, the perimeter is approximately 28.98 or 10 + 6√10
Best of Luck!
I believe it’s 9 but unsure sorry
Area of a semicircle =
r² / 2
r= 5/2 = 2.5
So: A= 3.14 x 2.5² / 2 A = 9.8125 so rounding to the nearest hundredth is A=9.81
I do not understand this problem
1 / cos^2 O - 3 / cos O - 2 = 0
1 - 3 cos O - 2 cos^2 O = 0
2 cos^2 O + 3 cos O - 1 = 0
cos O = 0.2807 , -1.78 ( -1.78 cannot be a solution)
O = 74 degrees (from 0.2807) another solution is 360-74 = 286 degrees
Its D