A certain survey conducted had a population proportion of at most 22% for people who agreed. What is the confidence level if 20% of the people sampled agreed, and the standard error of the proportion is ±1%?
1 answer:
The
formula for the population proportion is:
n = p ± Zc
where p =
confidence level = 0.2
n =
proportion = 0.22
= standard error = 0.01
Finding for Zc:
.20+(.01)=.22
Zc = 2
Referring to Critical value table for standard
normal curve, a Zc value of 2 is equivalent to 95% Confidence Level.
Answer: 95% Confidence Level
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