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sammy [17]
3 years ago
5

8 to the -2nd power times a to the 7th power

Mathematics
1 answer:
malfutka [58]3 years ago
8 0
A^7/64. When something is to a negative power, move it to the denominator. <span />
You might be interested in
Whatnis the greatest common factor of 7 and 19
viktelen [127]
7 and 19 are both prime numbers.
 
Factors of 7
1 * 7 = 7
7 * 1 = 7
factors are 1 and 7

Factors of 19
1 * 19 = 19
19 * 1 = 19
factors are 1 and 19

GCF = greater common factor
So GCF is 1 because there is no greater common number in the 7 and 19
7 0
4 years ago
Whts 2 + 2 ;-;..............
Katarina [22]

Answer:

i think it's 4

Step-by-step explanation:

 2

+2

-------

4

3 0
3 years ago
Jess wants 144 cupcakes for her party. Jess already Mets 24 cupcakes, and 72 fudge cupcakes. How many more cupcakes does Jess ma
rewona [7]

Answer:

1. 48

2. 31.40

Step-by-step explanation:

I don't know if this right..

4 0
3 years ago
At the base of a pyramid, a surveyor determines that the angle of elevation to the top is °. At a point meters from the base, th
riadik2000 [5.3K]

Answer:

\frac{(\sin 18^\circ)}{75} = \frac{(\sin 35^\circ)}{x}

Step-by-step explanation:

Incomplete question:

<em></em>\angle CBD = 53^\circ<em></em>

<em></em>\angle CAB = 35^\circ<em></em>

<em></em>AB = 75<em></em>

<em></em>

<em>See attachment for complete question</em>

Required

Determine the equation to find x

First, is to complete the angles of the triangle (ABC and ACB)

\angle ABC + \angle CBD = 180 --- angle on a straight line

\angle ABC + 53= 180

Collect like terms

\angle ABC =- 53+ 180

\angle ABC =127^\circ

\angle ABC + \angle ACB + \angle CAB = 180 --- angles in a triangle

\angle ACB + 127 + 35 = 180

Collect like terms

\angle ACB =- 127 - 35 + 180

\angle ACB =18

Apply sine rule

\frac{\sin A}{a} = \frac{\sin B}{b}

In this case:

\frac{\sin ACB}{AB} = \frac{\sin CAB}{x}

This gives:

\frac{(\sin 18^\circ)}{75} = \frac{(\sin 35^\circ)}{x}

4 0
3 years ago
Read 2 more answers
What does k mean in this situation?
Yuliya22 [10]
I can’t see the variable k in the given picture
6 0
4 years ago
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