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sammy [17]
3 years ago
5

8 to the -2nd power times a to the 7th power

Mathematics
1 answer:
malfutka [58]3 years ago
8 0
A^7/64. When something is to a negative power, move it to the denominator. <span />
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F(x) = –3x² - 6x +1<br><br> Find f(8)
MAXImum [283]

Answer:

-239

Step-by-step explanation:

6 0
3 years ago
Find the value of x, rounded to the nearest tenth.<br>​
Step2247 [10]

Answer:

x = 18

Step-by-step explanation:

Given two intersecting chords inside a circle, then the product of the parts of one chord is equal to the product of the parts of the other chord, that is

7x = 21 × 6 = 126 ( divide both sides by 7 )

x = 18

3 0
3 years ago
Read 2 more answers
How many of the first million positive integers share no common factors greater than 1 with 2020
Bingel [31]

9514 1404 393

Answer:

  396,040

Step-by-step explanation:

Factors of 2020 are 2, 5, 101.

There are 1,000,000 / 1010 = 990 multiples of 2 and 5 and 101.

There are 1,000,000 / 505 -990 = 990 multiples of 5 and 101 only.

There are 1,000,000 / 202 -990 = 3,960 multiples of 2 and 101 only.

There are 1,000,000 / 10 - 990 = 99,010 multiples of 2 and 5 only.

There are 1,000,000 / 101 -990 -990 -3960 = 3,960 multiples of 101 only.

There are 1,000,000 / 5 -990 -990 -99,010 = 99,010 multiples of 5 only.

There are 1,000,000 / 2 -990 -3960 -99,010 = 396,040 multiples of 2 only.

So, the total number of multiples of any factor of 2020 is ...

  990 +990 +3960 +99,010 +3960 +99010 +396040 = 603960

Then the number of integers in the first million that do not share any common factors greater than 1 with 2020 is ...

  1,000,000 -603,960 = 396,040

4 0
3 years ago
Find 24% of $240.<br> $576<br> $57.60<br> $100<br> $10
frozen [14]

Answer:

The answer is B. 57.6

Step-by-step explanation:

240 x .24 = 57.6

4 0
3 years ago
JK= 4x+3,<br> JL= 47, <br> KL= 9x+5<br> Find KL
Anuta_ua [19.1K]

Answer:

<h2>x = 3</h2><h2></h2>

Step-by-step explanation:

JK + KL = JL

(4x + 3) + (9x + 5) = 47

4x + 9x = 47 - 3 - 5

13x = 39

x = 39 / 13

x = 3

4 0
3 years ago
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