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NemiM [27]
3 years ago
12

What is the percent increase from 25 to 95

Mathematics
2 answers:
FrozenT [24]3 years ago
8 0
280 Percent increase
iris [78.8K]3 years ago
4 0
280   %    increases hope that this helps

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What number is 10 times as much as 50
Murljashka [212]

Answer:

500

Step-by-step explanation:

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3 years ago
Which describes the median set of data
blagie [28]

In a set of data, to find the median you first have to order your data from greatest to least then find the center or (median) of your data. E is your answer.

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3 years ago
Which pair of triangles is congruent?
daser333 [38]
You are only showing one pair of triangles
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3 years ago
Express 1400 as a product of its prime factors in index form
exis [7]

Answer:

2^3 X5^2 X7

Step-by-step explanation:

Given the number: 1400

A number is said to be prime when it can only be divided by 1 and itself.

We can express 1400 as a product of its prime numbers by gradually decomposing it into smaller units.

1400=14X100\\14=2X7\\100=10X10=2X5X2X5\\$Therefore:\\1400=2 X 7 X 2 X 5 X 5 X 5\\Reorganising\\1400=2 X 2 X 2 X 5 X 5 X 7\\Therefore, 1400 expressed as a product of its prime factors is:\\1400=2^3 X5^2 X7

7 0
3 years ago
I need to find all real values of x from this inequality x^2>2x-2 and also this question x^2>2x+2. I need the answer fast
sergeinik [125]

x^2\gt2x-2

x^2-2x+2\gt0

You are essentially asking at this point where is the quadratic function greater than 0. To get the interval find the roots. Between the roots the function is guaranteed to be LESS THAN zero. Everywhere else the function is greater than 0.

x^2-2x+2=0

Use Vieta's rule to get the roots,

(x-1)(x-1)=0

Both roots are the same so no value is less than 0 which means all values except at the point of root are strictly greater, the point of root is at x_{1,2}=1 which means the set for which the quadratic function is greater than 0 is \mathbb{R}-\{1\} "all real numbers except 1".

To convert this into interval notation use all numbers up to 1 but not including and all numbers after 1 but not including,

(-\infty,1)\cup(1,\infty)

Hope this helps :)

7 0
3 years ago
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