Question

What is the equation of a line with a x-intercept of −2 and a y-intercept of 10?

Answer 1

Hey there! :)

Answer:

y = 5x + 10

Step-by-step explanation:

From the information given, we can derive the points (-2, 0) and (0, 10). Find the slope using the slope formula:

$m = \frac{\text{rise}}{\text{run}} = \frac{y_2 - y_1}{x_2 - x_1}$

Plug in the points:

$m= \frac{10 - 0}{0 - (-2)}$

Simplify:

$m= \frac{10}{2}$

m = 5.

The equation in slope-intercept form is y = mx + b. We were already given the b value, or y-intercept as y = 10. Therefore:

y = 5x + 10 is the equation written in slope-intercept form.

Answer 2

Answer:

y=5x+10

Step-by-step explanation:

The base form of the equation is y=mx+b

B is always the y intercept so we can plug that in

y=mx+10

Then we can fine the slope by using the gradient formula

Change in y over change in x

The two points are (-2, 0) and (0, 10)

The result is 10/2 which can be simplified to 5

y=5x+10