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Vlad [161]
3 years ago
6

I need help with the rule!!!

Mathematics
2 answers:
alukav5142 [94]3 years ago
5 0
Reflect across the x-axis since the corresponding points are equal distance from the x-axis
Alona [7]3 years ago
3 0
Reflect over the x axis
You might be interested in
-6 minus -2 1/2<br>step by step explanation please ​
tatuchka [14]

Turn fraction into a decimal.

-2 1/2 = -2.5

Remember that when you subtract a negative number it automatically changes it to adding a positive number.

-6 + 2.5 = -3.5

Hope This Helped! Good Luck!

7 0
3 years ago
Read 2 more answers
What is the missing justification?
Vikki [24]

Transitive property is your answer

if ∠A ≅ ∠C, and ∠C ≅ ∠B then, ∠A ≅ ∠B

hope this helps

4 0
3 years ago
Read 2 more answers
In 1995, Hazel was 25 years older than her son Gary. In 2022, Hazel's age will be 150% of Gary's age. How old were they in 1995?
Kitty [74]
So find the difference between 1995 and 2022 to make it easier
2022-1995=27

so the rephrased question is
when hazel was x years old, she was 25 years older than son gary who was y old at that time (equation is x is 25 more than y or x=25+y)
in 27 years, (this means x+27 and y+27) hazel's age will be 150% of gary's age (x+27= 150% of y+27)
percent means parts out of 100  so 150%=150/100=15/10=1.5
'of' in math means multiply so
the equations are
x=25+y
x+27=1.5(y+27)
subsitute 25+y for x in second euation
25+y+27=1.5(y+27)
add like terms
y+52=1.5(y+27)
I personally dislike decimals to multiply both sides by 2 to make 2 0.5's or 1 (you are technically supposed to distribute or divide both sides by 1.5) so
2y+104=3(y+27)
distribute
2y+104=3y+81
subtract 2y from both sides
104=y+81
subtract 81 from both sides
23=y
subsitute
x=25+y
x=25+23
x=48


Hazel was 48 and Gary was 23 in the year of 1995
5 0
3 years ago
Find the sum of (x+5), (-4x-2), and (2x-1)
RideAnS [48]
I think the answer is -x+2.
3 0
3 years ago
Can someone explain this step by step for me? its from a review so ignore my wrong answer. Thank you!
Andrei [34K]

Answer:

P(\text{Male}|\text{Divorced})\approx0.092

Step-by-step explanation:

\displaystyle P(\text{Male}|\text{Divorced})=\frac{P(\text{Male and Divorced})}{P(\text{Male})}=\frac{\frac{9.6}{214.7}}{\frac{104.5}{214.7}}\approx0.092

We can even break this down further by simply only looking at the total amount of males, and finding the proportion of males that are divorced, which is \frac{9.6}{104.5}\approx0.092, the same value.

Note that P(Male | Divorced) means the probability of choosing a male, given (|) that person is divorced.

7 0
2 years ago
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