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Alik [6]
3 years ago
13

Sam’s two new aquariums each hold exactly 200 gallons of water. One aquarium will hold small fish and the other will hold large

fish. Now he needs new fish for his aquariums. He will buy 5 small fish for every 10 gallons of water in the aquarium. He will buy 8 large fish for every 40 gallons of water in the aquarium. What is the total number of fish Sam will have? What will be the ratio of Sam’s small fish to large fish? Show or explain the steps you used to solve this problem.
Mathematics
2 answers:
Gre4nikov [31]3 years ago
7 0
Okay so you have to do 5 times 10 then you will have to do 8 time 8 times 40 so after you get your answer you would do the ratio 50 to 320 50:320
svetlana [45]3 years ago
5 0

Answer:

5 times 10 then you will have to do 8 time 8 times 40 so after you get your answer you would do the ratio 50 to 320 50:320

Step-by-step explanation:

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He mean potassium content of a popular sports drink is listed as 140 mg in a 32-oz bottle. Analysis of 20 bottles indicates a sa
mezya [45]

Answer: (A) H0: μ = 140 mg vs. H1: μ ≠ 140 mg

Step-by-step explanation:

Usually null hypothesis represents the claim that the values associated to the groups being tested have no statistical difference but alternative hypothesis supports the claim that there is statistical difference.

Let \mu be the population mean .

We are given that the mean potassium content of a popular sports drink is listed as 140 mg in a 32-oz bottle.

i.e. Null hypothesis :H_0:\mu=140

Alternative hypothesis for two tail hypothesis has sign (≠).

i.e. Alternative hypothesis : H_1 : \mu\neq140

∴ The hypotheses for a two-tailed test of the claimed potassium content:

H0: μ = 140 mg vs. H1: μ ≠ 140 mg

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4 years ago
Find the distance between two points. ENTER THE NUMBER THAT GOES BENEATH THE RADICAL SYMBOL.
iVinArrow [24]
<h2>The distance between two points is \sqrt{98} or 9.9 units</h2>

<em><u>Solution:</u></em>

<em><u>The distance between two points is given as:</u></em>

d = \sqrt{(x_2-x_1)^2 + (y_2-y_1)^2}

From given,

(x_1, x_2) = (-5, 5)\\\\(x_2, y_2) = (2, -2)

<em><u>Substituting the values we get,</u></em>

d = \sqrt{(2+5)^2+(-2-5)^2}\\\\d = \sqrt{7^2+(-7)^2}\\\\d = \sqrt{49+49}\\\\d = \sqrt{98}\\\\d = 9.899 \approx 9.9

Thus the distance between two points is \sqrt{98} or 9.9 units

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Step-by-step explanation:

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