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2 years ago

Can someone give me the answers to these please

Mathematics

1 answer:

vodomira [7]2 years ago

7 0

Answer: 1. slope = -5

2. BDC = 237

Step-by-step explanation:

1. y = mx + b

m= slope

y = -5x + 7

m = -5

2. Angle AOB = 57

Angle AOC = 180

Arc BC = 180 - 57 = 123

Arc BDC = 360 - Arc BC = 360 - 123 = 237

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Are this too answer correct

Ede4ka [16]

I believe so friend budddy

4 0

2 years ago

. A square picture frame occupies an area of 112 ft2 . What is the length of each side of the picture in simplified radical form

saw5 [17]

Recall that a square is just a rectangle with all sides equal.

and the area of a rectangle is just length * width.

$\bf \textit{area of a rectangle}\\\\
A=length\cdot width\quad 
\begin{cases}
length=x\\
width=x\\
A=112
\end{cases}\implies 112=x\cdot x\implies 112=x^2
\\\\\\
\sqrt{112}=x\implies \sqrt{16\cdot 7}=x\implies \sqrt{4^2\cdot 7}=x\implies 4\sqrt{7}=x$

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3 years ago

PLEASE HELP IMMEDIATELY!!!! Find x when – Negative one-half + x = –Negative StartFraction 21 over 4 EndFraction. – Negative Star

balu736 [363]

Answer:

-61/4

Step-by-step explanation:

-1/2 + x = - 21/4 - 23/4 - 19/4

-1/2 + x = -(21+23+19)/4

x = -63/4 + 1/2

x= -63/4 + 2/4

x = -61/4

Hope that helps, tell me if you need further explanation. =)

3 0

3 years ago

Read 2 more answers

What is the area of triangle pqr on the grid? a triangle pqr is shown on a grid. the vertex p is on ordered pair 7 and 6, vertex

horsena [70]

P(7,6), Q(1,6), R(4,2)

We have PQ parallel to the x axis. We'll call that the base,

b = 7 - 1 = 6

The altitude is then the y difference h = 6 - 2 = 4

The area is $\frac 1 2 bh = \frac 1 2 (6)(4) = 12$

Answer: 12 square units

In general we can use the shoelace formula for the area of any polygon given coordinates. We write the points like this:

(7,6), (1,6), (4,2)

(1,6), (4,2), (7,6)

The area is then half the absolute value of the sum of the cross products:

$A = \frac 1 2 | 7(6)-6(1) + 1(2)-6(4) + 4(6)-2(7) | = \frac 1 2 |24| = 12$

6 0

3 years ago

Read 2 more answers

5/4 to 3/8 as a percent change

Digiron [165]

Well, what's the diffrence from 5/4 to 3/8?

$\bf \cfrac{5}{4}-\cfrac{3}{8}\qquad \stackrel{\textit{LCD is 8 clearly}}{\implies }\qquad \cfrac{10-3}{8}\implies \cfrac{7}{8}$

so, if we take 5/4 to be the 100%, what is 7/8 off of it in percentage anyway?

$\bf \begin{array}{ccll}
amount&\%\\
\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\
\frac{5}{4}&100\\\\
\frac{7}{8}&x
\end{array}\implies \cfrac{\quad \frac{5}{4}\quad }{\frac{7}{8}}=\cfrac{100}{x}\implies \cfrac{5}{4}\cdot \cfrac{8}{7}=\cfrac{100}{x}
\\\\\\
\cfrac{40}{28}=\cfrac{100}{x}\implies x=\cfrac{28\cdot 100}{40}$

5 0

2 years ago