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andrew11 [14]
3 years ago
11

A glacier in Alaska moves about 29.2 meters a day.

Mathematics
1 answer:
Leto [7]3 years ago
3 0

Answer:

29,100

Step-by-step explanation:

29.1 × 10 = 291

29.1 × 100 = 2,910

29.1 × 1000 = 29,100

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Mister Rogers is fencing another new rectangular garden in his neighborhood. One side of the garden faces the road and needs to
Oksanka [162]

Answer:

length of the pretty side  and length of the side oppositte to the pretty side  =   37.91 ft

length of the other two sides  = 27.52 ft

Step-by-step explanation:

The mathematical problem is:

Max A = b1*h

subject to: 35*b1 + 18*(2*h + b2) <= 3000

Where

A: area of the garden

b1: length of the pretty side

b2: length of the side oppositte to the pretty side

h: length of the other two sides

Replacing with b1 = b2 and taking only the equality sign in the restriction (in the maximum all the money will be spent), we get:

35*b1 + 18*(2*h + b1) = 3000

35*b1 + 36*h + 18*b1 = 3000

53*b1 + 36*h = 3000

b1 = 3000/53 - (36/53)*h

Substituing in Area's formula  

A = (3000/53 - (36/53)*h)*h

A = (3000/53)*h - (36/53)*h^2

In the maximum, the derivative of A is equal to zero

dA/dh = 3000/53 - 2*(36/53)*h =

3000/53 - 72/35*h = 0

h = (3000/53)*(35/72)

h = 27.52 ft

then,

b1 = 3000/53 - (36/53)*27.52

b1 = 37.91 ft =b2

3 0
3 years ago
What are other ways to write 20,000,000
Klio2033 [76]
2×10 to the 7th power
3 0
3 years ago
Triangle EFG has coordinates E (-4,4), F (-4,-2), and G (2,-2). Triangle JKL will be a dilation of triangle EFG with a scale fac
denis-greek [22]

The point L is plotted at A. (1, -1).

Step-by-step explanation:

Step 1:

First, we plot the coordinates of both triangles.

The coordinates of the triangle EFG are as follows;

E = (-4, 4), F = (-4, -2), and G = (2, -2).

The coordinates of triangle JKL are;

J = (-2, 2), K = (-2, -1), and L = (x, y).

Step 2;

Next, we need to find the distances between at least two coordinates for both triangles.

The distances between vertical lines are found by calculating the difference in y values while for horizontal lines, the distances are found by calculating the difference between the x values.

The distance of EF = 4-(-2) =6.

The distance of JK = 2-(-1)= 3.

The distance of FG =2-(-4)= 6.

The distance of KL =  (Scale factor)(the distance of FG),

The distance of KL= (\frac{1}{2} )(6) = 3.

Step 3;

So the point L is 3 points away from point k on the x axis.

(x, y) = (-2+3, 1) = (1, -1).

So point L is plotted at option A. (1, -1).

8 0
3 years ago
Could i have some really really quick help?
nata0808 [166]

Answer:

1125 m

Step-by-step explanation:

Given equation:

h=-5t^2+150t

where:

  • h = height (in metres)
  • t = time (in seconds)

<u>Method 1</u>

Rewrite the equation in vertex form by completing the square:

h=-5t^2+150t

\implies h=-5t^2+150t-1125+1125

\implies h=-5(t^2-30t+225)+1125

\implies h=-5(t-15)^2+1125

The vertex (15, 1125) is the turning point of the parabola (minimum or maximum point).  As the leading coefficient of the given equation is negative, the parabola opens downward, and so vertex is the maximum point.  Therefore, the maximum height is the y-value of the vertex: 1125 metres.

<u>Method 2</u>

Differentiate the function:

\implies \dfrac{dh}{dt}=-10t+150

Set it to zero and solve for t:

\implies -10t+150=0

\implies 10t=150

\implies t=15

Input found value of t into the original function and solve for h:

\implies -5(15)^2+150(15)=1125

Therefore, the maximum height is 1125 metres.

8 0
2 years ago
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Brut [27]
3.1 if i’m not mistaken
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