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zhannawk [14.2K]
3 years ago
13

haiely created another problem involving 2 rectangles she says 2 rectangles have the same area javito says that her statement is

impossible is she correct ? explain the first rectangle says 2in &xin and the other rectangle says 5in &(x+3)in
Mathematics
1 answer:
Verizon [17]3 years ago
8 0
Her statement is possible, the first rectangle could be equal to the second  because x is unknown so if x was 5in in the first rectangle and - 1 in the second rectangle both problems would look like this 2 in & 5 in and the second one 5in & (2 in =  (-1 +3)).

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Solve for a: 2a + 8b = 4c
professor190 [17]
The answer is
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8 0
3 years ago
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There are 12 books on a shelf 5 of these books are new the rest are used what is the ratio of new books to used books
tiny-mole [99]

Answer:

5:7

Step-by-step explanation:

Basically you first find the amount of the books are the shelf knowing that you have 5 new books, you subtract the amount of new books from total books. And 5:7 can't be simplified any further making 5:7 the answer.

5 0
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Cos(-170°) = _____<br><br> -cos10°<br> cos10°<br> cos(-10°)
ikadub [295]

<em>The right answer for:</em>

<em>cos(-170°) = _____</em>

<em>is:</em>

<em>-cos10°</em>

<h2>Explanation:</h2>

The cosine function is an even function, which means that for every point (x,y) on the graph of y=cos(x) then the point (-x,y) also lies on the graph of the function. In other words, we can write:

cos(-170^{\circ})=cos(170^{\circ})

But:

170^{\circ}=180^{\circ}-10^{\circ}

So:

cos(170^{\circ})=cos(180^{\circ}-10^{\circ})

By property:

cos(a-b)=cosacosb+sinasinb \\ \\ a=180^{\circ} \\ \\ b=10^{\circ} \\ \\ cos(170^{\circ} )=cos(180^{\circ} -10^{\circ})=cos180^{\circ} cos10^{\circ} +sin180^{\circ} sin10^{\circ} \\ \\  cos(170^{\circ})=-cos(10^{\circ})+0 \\ \\ \boxed{cos(170^{\circ})=-cos(10^{\circ})}

<h2>Learn more:</h2>

Trigonometric functions: brainly.com/question/2680050

#LearnWithBrainly

4 0
3 years ago
How do I solve this problem
quester [9]
I think x equals 54


Hope this helps
4 0
3 years ago
Please help. Give answer and why its the answer. <br>I will give brainliest!
777dan777 [17]
(a) False. The number 7 is NOT an element of set B as 7 is not in the set B (2, 3, 4 and 0 are though)

(b) False. 3 is a member of set A. It is the third element listed in the set. So saying "3 is not a member of set A" is a false claim

(c) True. The value 0 is found in set B. It is the last element listed. 

Final Answer: Choice C) 
7 0
3 years ago
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