1. (3 + xz)(–3 + xz)
2. (y² – xy)(y² + xy)
3. (64y2 + x2)(–x2 + 64y2)
Explanation
The difference of 2 squares is in the form (a+b)(a-c).
(3 + xz)(–3 + xz) = (3 + xz)(xz -3)
= (xz + 3)(xz - 3)
= x²y²-3xy+3xy-9
=x²y² - 3²
(y² – xy)(y² + xy) = y⁴+xy³-xy³-x²y²
= y⁴ - x²y²
(64y2 + x2)(–x2 + 64y2)= (64y²+x²)(64y²-x²)
= 4096y⁴-64y²x²+64y²x²-x⁴
= 4096y⁴ - x⁴
Answer:
52 is the size of the sample space of this two-stage experiment
200 is the median (50%) of the data represented in the box plot. The fraction of the books has 200 or fewer pages is: 1/2.
<h3>What is the Median of a Data in a Box Plot?</h3>
In a box plot, the median is indicated as the value marked by the vertical line that divides the rectangular box of the box plot.
The median is the middle of the data and represents the 50th percentile. That is 1/2 the data.
In the box plot given, 200 pages is the median. Therefore, the fraction of the books that have 200 or fewer pages is: 1/2.
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By the Central Limit Theorem, the best point estimate for the mean GPA for all residents of the local apartment complex is 1.7.
The Central Limit Theorem established that, for a normally distributed random variable X, with mean and standard deviation, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean and standard deviation ;
For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.
In this problem, we have that:
The sample of 112 residents has a mean GPA of 1.7.
By the Central Limit Theorem, the best point estimate for the mean GPA for all residents of the local apartment complex is 1.7.
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The answer would be 90 line ups
This is because 18 x 5 = 90
