Answer: There are 97 nickels and 108 quarters.
Step-by-step explanation:
Let x = Number of nickels, y = Number of quarters.
As per given,
x+y = 205 ...(i)
0.05x+0.25y = 31.85 ... (ii) [1 nickel = $0.05, 1 quarter = $ 0.25]
Multiply (ii) by 20, we get
x+5y=637 ...(iii)
Eliminate (i) from (iii)
4y = 432
⇒ y = 108 [Divide both sides by 4]
Put value of y in (i), we get
Hence, there are 97 nickels and 108 quarters.
Solve:
"<span>twice the number minus three times the reciprocal of the number is equal to 1."
3(1)
Let the number be n. Then 2n - ------- = 1
n
Mult all 3 terms by n to elim. the fractions:
2n^2 - 3 = n. Rearranging this, we get 2n^2 - n - 3 = 0.
We need to find the roots (zeros or solutions) of this quadratic equation.
Here a=2, b= -1 and c= -3. Let's find the discriminant b^2-4ac first:
disc. = (-1)^2 - 4(2)(-3) = 1 + 24 = 25.
That's good, because 25 is a perfect square.
-(-1) plus or minus 5 1 plus or minus 5
Then x = ------------------------------ = --------------------------
2(2) 4
x could be 6/4 = 3/2, or -5/4.
You must check both answers in the original equation. If the equation is true for one or the other or for both, then you have found one or more solutions.</span>
55 adult tickets. Set up 2 equations: c+a=125 and 6.1c+9.4a=944. Isolate either variable from first equation and plug into second to find that 55 adult tickets were sold and 70 children’s tickets
3(5)+15= 30
because BIDMAS so we would multiply 3 by 5 then add the answer which would be 15 to 15 and we would get 30.
