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Gala2k [10]
3 years ago
9

In a survey of 150 students, 90 students were taking algebra and 30 were taking biology. What is the least number of students wh

o could have been taking both courses? What is the greatest number of students who could be taking both courses? What is the greatest number of students who could have been taking neither course?
Mathematics
2 answers:
Alex787 [66]3 years ago
7 0

30 students with a course and 60 with  out
Reil [10]3 years ago
5 0
30 students could of been taking both courses and 60 with no course
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The ceiling of Katie’s living room is a square that is 15 ft long on each side. To decorate for a party, she plans to hang crepe
egoroff_w [7]

Answer:

<u><em>6</em></u> rolls because the total perimeter is 102 ft and five rolls is only 100 feet. So she needs <em><u>6</u></em> rolls.

Step-by-step explanation:

to find perimeter, add up all the side lengths.

so 15*4 (it's easier than 15+15+15...)

60 ft.

now we have to use Pythagorean's Theorum to find corner to corner.

so a^2+b^2=c^2

we have a and b

15^2+15^2=c^2

do the math...

225+225= 450

square root of 450=

21.213

double that because it's used twice (corner to corner and corner to corner)

42.426

now add it all up

42.426 + 60 = 102.426

we can round

102

20*5 = 100

so she needs 6

MY ORIGINAL ERROR WAS 5, BUT 5 TIMES 20 IS ONLY 80, SO THEREFORE 6 IS REQUIRED SO THERE IS ENOUGH TO COVER 102.

6 0
3 years ago
A piece of wire of length 6363 is​ cut, and the resulting two pieces are formed to make a circle and a square. Where should the
Lerok [7]

Answer:

a.

35.2792 cm from one end (The square)

And 27.7208 cm from the other end (The circle)

b. See (b) explanation below

Step-by-step explanation:

Given

Length of Wire ,= 63cm

Let L be the length of one side of the square

Circumference of a circle = 2πr

Perimeter of a square = 4L

a. To minimise

4L + 2πr = 63 ----- make r the subject of formula

2πr = 63 - 4L

r = (63 - 4L)/2π

r = (31.5 - 2L)/π

Let X = Area of the Square. + Area of the circle

X = L² + πr²

Substitute (31.5 - 2L)/π for r

So,

X² = L² + π((31.5 - 2L)/π)²

X² = L² + π(31.5 - 2L)²/π²

X² = L² + (31.5 - 2L)²/π

X² = L² + (992.25 - 126L + 4L²)/π

X² = L² + 992.25/π - 126L/π +4L²/π ------ Collect Like Terms

X² = 992.25/π - 126L/π + 4L²/π + L²

X² = 992.25/π - 126L/π (4/π + 1)L² ---- Arrange in descending order of power

X² = (4/π + 1)L² - 126L/π + 992.25/π

The coefficient of L² is positive so this represents a parabola that opens upward, so its vertex will be at a minimum

To find the x-cordinate of the vertex, we use the vertex formula

i.e

L = -b/2a

L = - (-126/π) / (2 * (4/π + 1)

L = (126/π) / ( 2 * (4 + π)/π)

L = (126/π) /( (8 + 2π)/π)

L = 126/π * π/(8 + 2π)

L = (126)/(8 + 2π)

L = 63/(4 + π)

So, for the minimum area, the side of a square will be 63/(4 + π)

= 8.8198 cm ---- Approximated

We will need to cut the wire at 4 times the side of the square. (i.e. the four sides of the square)

I.e.

4 * (63/(4 + π)) cm

Or

35.2792 cm from one end.

Subtract this result from 63, we'll get the other end.

i.e. 63 - 35.2792

= 27.7208 cm from the other end

b. To maximize

Now for the maximum area.

The problem is only defined for 0 ≤ L ≤ 63/4 which gives

0 ≤ L ≤ 15.75

When L=0, the square shrinks to 0 and the whole 63 cm wire is made into a circle.

Similarly, when L =15.75 cm, the whole 63 cm wire is made into a square, the circle shrinks to 0.

Since the parabola opens upward, the maximum value is at one endpoint of the interval, either when

L=0 or when L = 15.75.

It is well known that if a piece of wire is bent into a circle or a square, the circle will have more area, so we will assume that the maximum area would be when we "cut" the wire 0, or no, centimeters from the

end, and bend the whole wire into a circle. That is we don't cut the wire at

all.

7 0
3 years ago
6 pints of glaze it takes 7/8 of a long for a bowl now many bowls can you glaze
lubasha [3.4K]

Answer:

ok so umm i dont get what ur looking for?

Step-by-step explanation:

3 0
3 years ago
Use the information to complete the task.
murzikaleks [220]

Answer:

14.25 - d

Step-by-step explanation:

8 0
3 years ago
What is the product of the polynomials below? (4x^2-2x-4)(2x+4)
Travka [436]

Answer:  8x³ + 12x² - 16x - 16

<u>Step-by-step explanation:</u>

  (4x² - 2x - 4)(2x + 4)

= (2x + 4)(4x² - 2x - 4)

= 2x(4x² - 2x - 4)  +  4(4x² - 2x - 4)

=   8x³ - 4x² - 8x   +  16x² - 8x - 16

=   8x³ + (-4x² + 16x²) + (-8x - 8x) - 16

=   8x³ + 12x² - 16x - 16

7 0
3 years ago
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