Let c= cost to rent each other
Let t= cost to rent each other
2c+3t=25
6T+5T=49
Multiply the 2nd equation by (-2) and add equation together
2c+3t=25
-12c-10t= 98
2t=98
T=49
Put this value into the 1st equation solve c
2c+3(49)=49
2c+147=49
2c=98
C=49
Cost to each chair and table are same 49.
Answer:
-20,476
Step-by-step explanation:
Answer:
106
Step-by-step explanation:
divided 320 by 3
Answer:8x+2
Step-by-step explanation: