A bag contains 4 blue and 5 red counters. Two counters are chosen at random without replacement. What is the probability that th
e counters are both red?
1 answer:
Answer:
P(both are red) = 5/18
Step-by-step explanation:
total counters = 9
red counters = 5
P(both red) = P(R1) n P(R2)
5/9 * 4/8 =5/18
5/9 because the red counters are 5 and the total number of counters are 9.
I multiplied by 4/8 because, after selecting the first red counter without replacement, the remaining is 4 and the total decreases to 8.
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