What are two solutions of 3 + 4 |x/2 + 3| = 11?

1 answer:

Alex4 years ago

3 0

3 + 4abs(x/2 + 3) = 11 Subtract 3
4 abs(x/2 + 3) = 11 - 3
4 abs(x/2 + 3) = 8 Divide by 4
abs(x/2 + 3) = 8/4
abs(x/2 + 3) = 2

Solution 1
x/2 + 3 = 2 Subtract 3
x/2 = 2 - 3
x/2 = - 1 Multiply by 2
x/2 *2 = - 2
x = - 2

Solution 2
x/2 + 3 = - 2
x/2 = - 2 - 3
x/2 = - 5 Multiply by 2
x = -5 * 2
x = -10

Solutions
x = - 2 <<<< answer 1
x = -10 <<<< answer 2

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Find the slope of the line that passes through the pair of points

professor190 [17]

$Slope= \frac{y_2-y_1}{x_2-x_1} = \frac{-\frac{9}{2} - (-1)}{-2- (-\frac{5}{3})}=\frac{ - \frac{9}{2} + 1}{-2 + \frac{5}{3}} \\= \frac{ - \frac{7}{2}}{ - \frac{1}{3}} \\= \frac{ - \frac{7}{2}\cdot6}{ - \frac{1}{3}\cdot6} \\=\frac{-21}{ -2} \\ =\boxed{\bf{ \frac{21}{2}}}$

So... none of your answers are correct. The correct answer is 21/2.

6 0

4 years ago

Pls help me help me help me

Ganezh [65]

Answer:

C. -3/2

Step-by-step explanation:

Perpendicular lines have negative reciprocal slopes.

We know that line m is perpendicular to line l.

Line l has a slope of 2/3. To find the slope of line m, find the negative reciprocal of 2/3.

Negative: switch the sign

2/3 --> -2/3