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3 years ago

14

Mrs tarter spends 15 percent of each weekday traveling in her car how many hours per day does mrs tarter spend in her car during

the week

2 answers:

Andrews [41]3 years ago

8 0

There are 5 week days which is 120hours.15%of 120 hours is
120*.15=18 hours per week

Greeley [361]3 years ago

4 0

There are 7 weekdays this means 168 hours so 168 times 0.15 is 25.2 hours a week

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Please help will mark brainliest

Ivenika [448]

Answer:

It should be -64

Step-by-step explanation:

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2 years ago

Which transformations are needed to change the parent some function to the sine function below?

Harrizon [31]

Beginning with the function y = sin x, which would have range from -1 to 1 and period of 2pi:
Vertical compression of 1/2 compresses the range from -1/2 to 1/2
Phase shift of pi/2 to the left
Horizontal stretch to a period of 4pi, as the crests are at -4pi, 0, 4pi
Vertical shift of 1 unit up moves the range to 1/2 to 3/2
So the first choice looks like a good answer.

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3 years ago

Read 2 more answers

Laura lives 15 miles east of Kevin’s place. Kevin lives 8 miles south of Michelle’s place. How far does Michelle live from Laura

My name is Ann [436]

Answer:

17 miles.

Step-by-step explanation:

Let's define:

North as the positive y-axis

East as the positive x-axis.

We know that Laura lives 15 miles east of Kevin's place.

Kevin lives 8 miles south of Michelle's place.

So, if we define the origin, (0, 0) as Laura's place.

From:

"that Laura lives 15 miles east of Kevin's place."

We have that the location of Kevin's house is 15 miles west from Laura's place, then Kevin's house is at:

(0, 0) + (-15mi, 0) = (-15mi, 0)

From Kevin lives 8 miles south of Michelle's place, we know that Michelle's live 8 miles north of Kevin's place.

Then the location of Michele's house is the location of Kevin's plus (0, 8mi).

Michelle's house is located at:

(-15mi, 0) + (0, 8mi) =(-15mi, 8mi)

Now we want to find the distance between Michelle's house and Laura's house.

Michelle's house is at (-15mi, 8mi)

Laura's house is at (0mi, 0mi)

Remember that the distance between two points (a, b) and (c, d) is given by:

$D = \sqrt{(a - c)^2 + (b - d)^2}$

Then the distance between (-15mi, 8mi) and (0mi, 0mi) is:

$D = \sqrt{(-15mi - 0mi)^2 + (8mi - 0mi)^2} = 17mi$

The correct option is the first one, 17 miles.

6 0

3 years ago

When you find f(2) for a given function f, you are finding the y value associated with x= 2

sveticcg [70]

Answer:

The provided statement is TRUE.

Step-by-step explanation:

The function <em>f</em> is an expression in variable <em>x</em>.

The entire expression can either be denoted by f (x) or <em>y</em>.

For instance consider the quadratic expression:

f (x) = ax² + bx + c

≡ y = ax² + bx + c

So, on computing the value of f (2), it implies that we are computing the value of y for <em>x</em> = 2.

Thus, the provided statement is TRUE.

4 0

3 years ago

Peter is trying to buy fencing for the perimeter of his garden. His garden is in the shape of a rectangle with a length of 2(x+6

MAVERICK [17]

Given that, the length of the garden is 2(x+6)feet and width is 3.5x feet.

So, length : l = 2(x+6) and width = 3.5x.

To find the fence of the garden we need to find the perimeter of the rectangle.

Formula to find the perimeter is:

p = 2l + 2b

= 2*2(x+6) + 2*3.5x

= 4(x+6) + 7x By multiplication.

= 4x + 24 + 7x By distribution property.

= 11x + 24 Combining the like terms.

So, he need to buy 11x + 24 feet fencing.

Hope this helps you!

4 0

3 years ago