Part 2:
-4a + 2 + 11a = 5a + 3 + 2a
~Combine like terms
7a + 2 = 7a + 3
~Subtract 2 to both sides
7a = 7a - 1
~Subtract 7a to both sides
0 = 1
Therefore, there are no solutions.
Best of Luck!
Answer:
when x=6, y=30
when x=7.5, y=37.5
Step-by-step explanation:
Just plug in the value of x into the equation y=5x
so when x=6, the equation will be y=5(6). In this case y=30
when x =7.5, the equation will be y=5(7.5). So y=37.5
600x1.07^11 = 1262
11 Months
Answer:
k=2
Problem:
if the equation x^2 +(k+2)x+2k=0 has equal roots,then the value of k is ..
Step-by-step explanation:
Since the coefficient of x^2 is 1, we can use this identity to aid us: x^2+bx+(b/2)^2=(x+b/2)^2.
So we want the following:
[(k+2)/2]^2=2k
Apply the power on the left:
(k+2)^2/4=2k
Multiply both sides by 4:
(k+2)^2=8k
Expand left side:
k^2+4k+4=8k *I used identity (x+c)^2=x^2+2xc+c^2
Subtract 8k on both sides:
k^2-4k+4=0
Factor using the identity mentioned a couple lines above:
(k-2)^2=0
Since zero squared is zero, we want k-2=0.
Adding both sides by 2 gives k=2.
Answer:
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Step-by-step explanation:
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