Answer:
1.
T mBAC = mB'A'C'
F 2mABC = mA'B'C'
F BC = 2B'C'
T 2XA = XA'
2
D'(-2/3; -1)
E'(-1;1)
F'(1;1)
G'(1;-1)
3
the centre is L(0;-2)
the scale factor is 4
length J'K' = 4JK
the measure of L is equal the measure of L'
<u>the</u><u> </u><u>table</u><u>:</u>
K(4;2) 4 4 16 16 0+16 -2+16 K'(16;14)
Answer:
- length: 32 in
- width: 21 in
Step-by-step explanation:
If the width of the original piece of sheet metal is x, then the length is 2x-10. Subtracting a 5" square from each corner makes the bottom of the box have dimensions (x-10) and (2x-20). The volume of the box is then ...
5(x -10)(2x -20) = 1210 . . . . . . volume is the product of the dimensions
10(x -10)² = 1210 = 10(11²) . . . . factor the equation
(x -10)² = 11² . . . . . . . . divide by 10
x = 11 + 10 = 21 . . . . . .take the square root, add 10
The length and width of the original piece of sheet metal were 32 inches and 21 inches, respectively.
Answer:
y=5
Step-by-step explanation:
4(y-6)=-4
4y-24=-4
+24 +24
4y=20
y=5
If all of the angles add up to 540 then you can divide it by 180 to see how many triangles it contains then from there you know that any polygon has 2 less triangles as it does sides. That means there are 5 sides
