H(x), or the range of this function, must be y >= 0, as you can never get a negative when square rooting any number.
For the domain, x cannot exceed -2 or 2, as this would mean we'd be finding the square root of a negative number, which can't happen without getting in to imaginary numbers. Thus, the domain must be -2 <= x <= 2.
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Two thirds is equal to 66.666666 etc. percent so 64 is pretty close to 66 so I would consider it right.
see the picture attached to better understand the problem
we know that
two tangent segments drawn from the same exterior point are congruent
so
JA=JB ,
LA=LC,
KC=KB
JA=13 units
LA=7 units
kC=10 units
hence
perimeter = JA+JB+LA+LC+KC+KB------> 13+13+7+7+10+10------> =60 units
therefore
the answer is
the perimeter of triangle JKL is 60 units
<span><span><span>9/10 - 7/20=(9x20) - (7x10)= 10x20= 110/200 110 divided by 10/ 200 divided by 10= 11/20. So that brings you to your answer of 11/20. hope this helps :)
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