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Kryger [21]
3 years ago
15

Please help :) I have no clue & math isn’t my strong subject.

Mathematics
1 answer:
melisa1 [442]3 years ago
7 0

Equation of a line that is perpendicular to given line is y=\frac{-7}{4} x+\frac{7}{4}.

Equation of a line that is parallel to given line is y=\frac{4}{7} x-\frac{69}{7}.

Solution:

Given line y=\frac{4}{7} x+4.

Slope of this line, m_1 = \frac{4}{7}

$\text{Slope of perpendicular line} = \frac{-1}{\text{Slope of the given line} }

                                   $m_2=\frac{-1}{m_1}

                                          $=\frac{-1}{\frac{4}{7} }

Slope of perpendicular line, m_2=\frac{-7}{4}

Passes through the point (–7, 5). Here x_1=-7, y_1=5.

Point-slope formula:

y-y_1=m(x-x_1)

$y-(-7)=\frac{-7}{4} (x-5)

$y+7=\frac{-7}{4} x+\frac{35}{4}

Subtract 7 from both sides, we get

$y=\frac{-7}{4} x+\frac{7}{4}

Equation of a line that is perpendicular to given line is y=\frac{-7}{4} x+\frac{7}{4}.

To find the parallel line:

Slopes of parallel lines are equal.

m_1=m_3

$m_3=\frac{4}{7}

Passes through the point (–7, 5). Here x_1=-7, y_1=5.

Point-slope formula:

$y-(-7)=\frac{4}{7} (x-5)

$y+7=\frac{4}{7} x-\frac{20}{7}

Subtract 7 from both sides,

$y=\frac{4}{7} x-\frac{69}{7}

Equation of a line that is parallel to given line is y=\frac{4}{7} x-\frac{69}{7}.

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The numerical representation and final elevation of the fish relative to sea level are :

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  • Final position = - 5.72

<u>Given the Parameters</u> :

Initial depth of fish = - 13.52

Change in elevation of fish = 7.8 feets

Positions below sea level are represented as negative values (-) ;

Hence, initial position of fish = - 13.52

Change in position = Rise in depth of 7.8 feets

<u>The numerical representation of the final position of the </u><u>fish</u><u> </u><u>can</u><u> </u><u>be</u><u> written thus</u> :

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Learn more : brainly.com/question/18109354

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