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3 years ago

Can someone please help me?

Mathematics

1 answer:

pochemuha3 years ago

8 0

Answer:

the picture is not clear can you take a new picture so I can help.

Step-by-step explanation:

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Triangle A B C is shown. Angle A C B is a right angle. An altitude is drawn from point C to a point on side A B to form a right

mars1129 [50]

Answer:

$BC=15\ units$

Step-by-step explanation:

see the attached figure to better understand the problem

In the right triangle ABC

Applying the Pythagorean Theorem

$AB^2=AC^2+BC^2$

substitute the given values

$17^2=8^2+BC^2$

solve for BC

$BC^2=17^2-8^2$

$BC^2=225$

$BC=15\ units$

5 0

2 years ago

Read 2 more answers

Is 143 a prime number

tensa zangetsu [6.8K]

143 is composite. To be prime it has to have only 2 divisors i.e it's self and one but since it has 4 divisors ( 143, 1, 11 and 13) it is composite.

5 0

3 years ago

Read 2 more answers

3^x= 3*2^x solve this equation

kompoz [17]

In the equation

$3^x = 3\cdot 2^x$

divide both sides by $2^x$ to get

$\dfrac{3^x}{2^x} = 3 \cdot \dfrac{2^x}{2^x} \\\\ \implies \left(\dfrac32\right)^x = 3$

Take the base-3/2 logarithm of both sides:

$\log_{3/2}\left(\dfrac32\right)^x = \log_{3/2}(3) \\\\ \implies x \log_{3/2}\left(\dfrac 32\right) = \log_{3/2}(3) \\\\ \implies \boxed{x = \log_{3/2}(3)}$

Alternatively, you can divide both sides by $3^x$ :

$\dfrac{3^x}{3^x} = \dfrac{3\cdot 2^x}{3^x} \\\\ \implies 1 = 3 \cdot\left(\dfrac23\right)^x \\\\ \implies \left(\dfrac23\right)^x = \dfrac13$

Then take the base-2/3 logarith of both sides to get

$\log_{2/3}\left(2/3\right)^x = \log_{2/3}\left(\dfrac13\right) \\\\ \implies x \log_{2/3}\left(\dfrac23\right) = \log_{2/3}\left(\dfrac13\right) \\\\ \implies x = \log_{2/3}\left(\dfrac13\right) \\\\ \implies x = \log_{2/3}\left(3^{-1}\right) \\\\ \implies \boxed{x = -\log_{2/3}(3)}$