4x-15=3x+12 how does this work out

Mathematics

2 answers:

guajiro [1.7K]4 years ago

8 0

First subtract 3x from itself and from 4x. Then the next problem will be (x-15=12). Add 15 to itself and to 12. Then the answer will be (x=27).

shepuryov [24]4 years ago

5 0

You have to find the value of x. first get x by its self on one side of the equation. so you have to add 15 to the -15 to cancel it out. what you do to one side of the equation you have to do to the other side so add 15 to 3x + 12. you should have 4x = 3x + 27. now since you only want the x on one side of the equals sign you have to subtract 3x from both sides of the equation to cancel out the 3x. you should have 1x = 27 or x = 27. now all you have to do is plug in the value of x ,27, into the original equations. 4(27) - 15 = 3(27) + 12.

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SVETLANKA909090 [29]

Answer:

Step-by-step explanation:

El problema se puede transcribir en esta ecuación:

2x + x = 168

siendo x las nectarinas

sumas los términos de x:

3x=168

despejas x:

x = 168 ÷ 3

x = 56

5 0

2 years ago

Help pls im being timed

Nitella [24]

The trigonometric ratios show that the angle FHE is 48.59°.

<h3>RIGHT TRIANGLE</h3>

A triangle is classified as a right triangle when it presents one of your angles equal to 90º. The greatest side of a right triangle is called hypotenuse. And, the other two sides are called cathetus or legs.

The math tools applied for finding angles or sides in a right triangle are the trigonometric ratios or the Pythagorean Theorem.

The Pythagorean Theorem says: $(hypothenuse)^2=(leg_1)^2+(leg_2)^2$ . And the main trigonometric ratios are:

$sin(\alpha) =\frac{opposite \;leg }{hypotenuse} \\ \\ cos(\alpha) =\frac{adjacent\;leg }{hypotenuse} \\ \\ tan(\alpha) =\frac{sin(\alpha )}{cos(\alpha )}= \frac{opposite \;leg }{adjacent\;leg } \\ \\$

It is important to remember that the sum of internal angles for any triangle is 180°.

From the question, it is possible to see 2 right triangles (HGF and FHE).

You can find the hypotenuse of the triangle HGF from the trigonometric ratio: sen Θ

$sin45=\frac{opposite\; leg }{hypotenuse} =\frac{\sqrt8}{hypotenuse}\\ \\ \frac{\sqrt{2} }{2} =\frac{\sqrt{8} }{hypotenuse} \\ \\ \sqrt{2}*hypotenuse=2\sqrt{8} \\ \\ hypotenuse=\frac{2\sqrt{8} }{\sqrt{2}} =2\sqrt{4} =2*2=4$

The hypotenuse of triangle HGF is one of legs for the triangle FHE. The, you can find the angle FHE from the trigonometric ratio: tan β. Thus,

$sin \beta =\frac{opposite\; leg }{adjacent\; leg} =\frac{3}{4}\\ \\ sin \beta=\frac{3}{4}=0.84806\\ \\ arcsin\beta =48.59^{\circ \:}$