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3 years ago

4x-15=3x+12 how does this work out

Mathematics

2 answers:

guajiro [1.7K]3 years ago

8 0

First subtract 3x from itself and from 4x. Then the next problem will be (x-15=12). Add 15 to itself and to 12. Then the answer will be (x=27).

shepuryov [24]3 years ago

5 0

You have to find the value of x. first get x by its self on one side of the equation. so you have to add 15 to the -15 to cancel it out. what you do to one side of the equation you have to do to the other side so add 15 to 3x + 12. you should have 4x = 3x + 27. now since you only want the x on one side of the equals sign you have to subtract 3x from both sides of the equation to cancel out the 3x. you should have 1x = 27 or x = 27. now all you have to do is plug in the value of x ,27, into the original equations. 4(27) - 15 = 3(27) + 12.

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First option is correct.

Since we have given that

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By Pythagoras theorem, we get that

$JL^{2}=JK^{2}+ KL^{2}\\JL^{2}=12^{2}+ 5^{2} \\JL^{2}=144+25= 169\\JL=13$

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Hence, First option is correct.

learn more about Pythagoras theorem and cosine ratios here:

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