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3 years ago

Do you know how to solve this problem?

Mathematics

1 answer:

zloy xaker [14]3 years ago

3 0

It's a graph it's a the answer is a

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Points M and N are both on ZB with M between Z and N. ZM = 10

maxonik [38]

Answer:

Your answer is 40%

Step-by-step explanation:

It is 20 units between Z and B.

We add 2 more points, and one of them is at the the halfway point of the entire line.(M)

One of them is only 2 units away from B.(N)

That means our line is halved, so from 20/20 possible places a point could go and land in the right area is now 10/20.

Minus 2 from that; to take into count of the N to B, and you have 8/20

8/20 is just 40%

5 0

3 years ago

Write the following inequality in slope-intercept form. –12x – 2y ≥ –42 y ≥ –6x – 21 y ≤ –6x – 21 y ≤ –6x + 21 y ≥ –6x + 21

xxMikexx [17]

Answer:

y ≤ –6x + 21

Step-by-step explanation:

5 0

3 years ago

4 x y -7y +9 x y + 12y

yulyashka [42]

Answer:13xy+5y

Step-by-step explanation:

5 0

4 years ago

An object is launched from ground level with an initial velocity of 120 meters per second. For how long is the object at or abov

babunello [35]

Answer:

D) 14 seconds

Step-by-step explanation:

First we will plug 500 in for y:

500 = -4.9t² + 120t

We want to set this equal to 0 in order to solve it; to do this, subtract 500 from each side:

500-500 = -4.9t² + 120t - 500

0 = -4.9t²+120t-500

Our values for a, b and c are:

a = -4.9; b = 120; c = -500

We will use the quadratic formula to solve this. This will give us the two times that the object is at exactly 500 meters. The difference between these two times will tell us when the object is at or above 500 meters.

The quadratic formula is:

$x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

Using our values for a, b and c,

$x=\frac{-120\pm \sqrt{120^2-4(-4.9)(-500)}}{2(-4.9)}\\\\=\frac{-120\pm \sqrt{14400-9800}}{-9.8}\\\\=\frac{-120\pm \sqrt{4600}}{-9.8}\\\\=\frac{-120\pm 67.8233}{-9.8}\\\\=\frac{-120+67.8233}{-9.8}\text{ or }\frac{-120-67.8233}{-9.8}\\\\=\frac{-57.1767}{-9.8}\text{ or }\frac{-187.8233}{-9.8}\\\\=5.3242\text{ or }19.1656$

The two times the object is at exactly 500 meters above the ground are at 5 seconds and 19 seconds. This means the amount of time it is at or above 500 meters is

19-5 = 14 seconds.

6 0

3 years ago

Square tiles are 5 inches long. They plan to make a row of tiles that is 4 feet 2 inches long. How many tiles are there needed t

Eduardwww [97]

Answer:

10 tiles

Step-by-step explanation:

4 feet 2 inches = 50 inches

50/5 = 10 tiles

4 0

3 years ago

Read 2 more answers