All categories

3 years ago

Solve for x: 2 over 10 equals 3 over quantity x minus 9

Mathematics

2 answers:

irinina [24]3 years ago

8 0

Answer:

The value of x in the given phrase is 24.

Step-by-step explanation:

Given phrase,

2 over 10 equals 3 over quantity x minus 9

$\frac{2}{10}=\frac{3}{x-9}$

By cross multiplication,

$2x-18=30$

Adding 18 on both sides,

$2x=48$

Divide both sides by 2,

$x=24$

Hence, the value of x is 24.

almond37 [142]3 years ago

4 0

Answer:

Step-by-step explanation:

2/10=3/x-9

2(x-9)=30

2x-18=30

2x=30+18

2x=48

x=24

You might be interested in

The baltimore ravens kansas city chiefs

FinnZ [79.3K]

What’s your question

6 0

3 years ago

Read 2 more answers

Suppose the time a child spends waiting at for the bus as a school bus stop is exponentially distributed with mean 7 minutes. De

Gala2k [10]

Answer:

The probability that the child must wait between 6 and 9 minutes on the bus stop on a given morning is 0.148.

Step-by-step explanation:

Let the random variable X represent the time a child spends waiting at for the bus as a school bus stop.

The random variable X is exponentially distributed with mean 7 minutes.

Then the parameter of the distribution is, $\lambda=\frac{1}{\mu}=\frac{1}{7}$ .

The probability density function of X is:

$f_{X}(x)=\lambda\cdot e^{-\lambda x};\ x>0,\ \lambda>0$

Compute the probability that the child must wait between 6 and 9 minutes on the bus stop on a given morning as follows:

$P(6\leq X\leq 9)=\int\limits^{9}_{6} {\lambda\cdot e^{-\lambda x}} \, dx$

$=\int\limits^{9}_{6} {\frac{1}{7}\cdot e^{-\frac{1}{7} \cdot x}} \, dx \\\\=\frac{1}{7}\cdot \int\limits^{9}_{6} {e^{-\frac{1}{7} \cdot x}} \, dx \\\\=[-e^{-\frac{1}{7} \cdot x}]^{9}_{6}\\\\=e^{-\frac{1}{7} \cdot 6}-e^{-\frac{1}{7} \cdot 9}\\\\=0.424373-0.276453\\\\=0.14792\\\\\approx 0.148$