What time is 100 minutes before 4:00 p.m.

2 answers:

7 0

2:20

60 minutes subtracted from 4 p.m. is 3 p.m. Since it was 100 minutes, there are 40 minutes to take away from 3 p.m.

Dafna1 [17]3 years ago

3 0

2:20 is the time because 40 minutes more from 2:20 is 3:00 and 60 minutes more is 4:00. Hope this helps!

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Two people start from the same point. One walks east at 4 mi/h and the other walks northeast at 8 mi/h. How fast is the distance

kvasek [131]

Answer:

5.89 mi/h

Step-by-step explanation:

This problem can be solved by using different methods. I will use vectors since it's the simplest way in which we can solve it. This can be solved by using related rates of change though.

First, we start by drawing a diagram with the velocity vectors.

A= velocity of the first person

B= velocity of the second person

C= velocity in which they are moving away from each other.

Since there is no acceleration in the problem, we can suppose we are talking about constant speeds, so the velocity at which they are moving away from each other will always remain constant. (It doesn't matter what time it is, the velocity will always be the same)

Having said this we can solve this problem by using the components, by using law of cosines or graphically. I will use law of cosines. The idea is to find the length of side c.

Law of cosines:

$C^{2}=A^{2}+B^{2}-2ABcos \gamma$

so we can solve the formula for C so we get:

$C=\sqrt{A^{2}+B^{2}-2ABcos \gamma}$

and now we can substitute the values we know:

$C=\sqrt{(4)^{2}+(8)^{2}-2(4)(8)cos 45^{o}}$

$C=\sqrt{16+64-32\sqrt{2}}$

$C=\sqrt{80-32\sqrt{2}} mph$

if we want an exact answer, then that will be the exact answer, which approximates to:

C=5.89 mph

4 0

3 years ago

Someone help me please!

andriy [413]

Answer:

To solve the first inequality, you need to subtract 6 from both sides of the inequality, to obtain 4n≤12. This can then be cancelled down to n≤3 by dividing both sides by 4. To solve the second inequality, we first need to eliminate the fraction by multiplying both sides of the inequality by the denominator, obtaining 5n>n^2+4. Since this inequality involves a quadratic expression, we need to convert it into the form of an^2+bn+c<0 before attempting to solve it. In this case, we subtract 5n from both sides of the inequality to obtain n^2-5n+4<0. The next step is to factorise this inequality. To factorise we must find two numbers that can be added to obtain -5 and that can be multiplied to obtain 4. Quick mental mathematics will tell you that these two numbers are -4 and -1 (for inequalities that are more difficult to factorise mentally, you can just use the quadratic equation that can be found in your data booklet) so we can write the inequality as (n-4)(n-1)<0. For inequalities where the co-efficient of n^2 is positive and the the inequality is <0, the range of n must be between the two values of n whereby the factorised expresion equals zero, which are n=1 and n=4. Therefore, the solution is 1<n<4 and we can check this by substituting in n=3, which satisfies the inequality since (3-4)(3-1)=-2<0. Since n is an integer, the expressions n≤3 and n<4 are the same. Therefore, we can write the final answer as either 1<n<4, or n>1 and n≤3.

5 0

3 years ago

Can someone please help me

pogonyaev

Answer:

(3,5)

Step-by-step explanation: