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3 years ago

I NEED HELP ASAP. thanks in advance solve the equation for x.

Mathematics

1 answer:

gtnhenbr [62]3 years ago

5 0

$3\sqrt[3]{10x+13}=21\\\\
\sqrt[3]{10x+13}=7\\\\
10x+13=343\\\\
10x=330\\\\
x=33$

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Someone help I just got new assignments 23,24,25,26,27,28,29, and 30

SSSSS [86.1K]

Answer:

23: y = -0.4

24: b = -1.8

25: m = 1/2

26: g = 1/4

27: s = 3/2

28: w = -12/5

29: z = 5/4

30: a = -9/5

Step-by-step explanation:

23:

$3y + 5.2 = -5y + 2$
$3y+5.2+5y=-5y+2+5y$
$8y + 5.2 = 2$
$8y+5.2-5.2=2-5.2$
$8y = -3.2$
$\frac{8y}{8} = \frac{-3.2}{8}$
$y = -0.4$

24:

$10b-2=7b-7.4$
$10b-2-7b=7b-7.4-7b$
$3b - 2 = -7.4$
$3b -2 + 2 = -7.4 + 2$
$3b = -5.4$
$\frac{3b}{3} = \frac{-5.4}{3}$

$b = -1.8$

25:

$2m - 2 = 6m - 4$
$2m-2-6m=6m-4-6m$
$-4m-2=-4$
$-4m-2+2=-4+2$
$-4m = -2$
$\frac{-4m}{-4} = \frac{-2}{-4}$
$m = \frac{1}{2}$

26:

$3g+5=7g+4$
$3g+5-7g=7g+4-7g$
$-4g+5=4$
$-4g + 5 - 5 = 4-5$
$-4g = -1$
$\frac{-4g}{-4} = \frac{-1}{-4}$
$g = \frac{1}{4}$

27:

$4s-1=-2s+8$
$4s-1+2s=-2s+8+2s$
$6s - 1 = 8$
$6s - 1 + 1 = 8+1$
$6s = 9$
$\frac{6s}{6} = \frac{9}{6}$
$s = \frac{3}{2}$

28:

$9w+3=4w-9$
$9w+3-4w=4w-9-4w$
$5w + 3=-9$
$5w + 3 - 3 = -9-3$
$5w = -12$
$\frac{5w}{5} = \frac{-12}{5}$
$w = \frac{-12}{5}$

29:

$6z-7=2z-2$
$6z-7-2z=2z-2-2z$
$4z -7 = -2$
$4z-7+7=-2+7$
$4z = 5$
$\frac{4z}{4} = \frac{5}{4}$
$z = \frac{5}{4}$

30:

$-a+3=4a+12$
$-a+3-4a=4a+12-4a$
$-5a+3=12$
$-5a + 3 - 3 = 12-3$
$-5a = 9$
$\frac{-5a}{-5} = \frac{9}{-5}$
$a = -\frac{9}{5}$

6 0

3 years ago

Find the Horizontal Tangent for x^3/3+3x^2-16x+9

bazaltina [42]

Answer:

The two horiz. tang. lines here are y = -3 and y = 192.

Step-by-step explanation:

Remember that the slope of a tangent line to the graph of a function is given by the derivative of that function. Thus, we find f '(x):

f '(x) = x^2 + 6x - 16. This is the formula for the slope. We set this = to 0 and determine for which x values the tangent line is horizontal:

f '(x) = x^2 + 6x - 16 = 0. Use the quadratic formula to determine the roots here: a = 1; b = 6 and c = -16: the discriminant is b^2-4ac, or 36-4(1)(-16), which has the value 100; thus, the roots are:

-6 plus or minus √100

x = ----------------------------------- = 2 and -8.

Evaluating y = x^3/3+3x^2-16x+9 at x = 2 results in y = -3. So one point of tangency is (2, -3). Remembering that the tangent lines in this problem are horizontal, we need only the y-coefficient of (2, -3) to represent this first tangent line: it is y = -3.

Similarly, find the y-coeff. of the other tangent line, which is tangent to the curve at x = -8. The value of x^3/3+3x^2-16x+9 at x = -8 is 192, and so the equation of the 2nd tangent line is y=192 (the slope is zero).

3 0

3 years ago

If 3x + 6 = 21, what does x + 2x plus 2 equal?

Alex777 [14]

Answer:

x+2x+2=17

Step-by-step explanation:

I'm assuming that's what you're asking, so here is the answer explanation.

3x+6=21

3x=15

Hence, x=5

Apply x=5 to x+2x=2

5+10+2

=17

3 0

2 years ago

Calcular: E = (sec245o + tg45o) ctg37o - 2cos60o

Vlada [557]

Answer:

$-2.813$

Step-by-step explanation:

Se simplifica inicialmente la fórmula en términos de las funciones trigonométricas fundamentales (Initially, the formula is simplified in terms of fundamental trigonometric functions):

$(\sec 245^{\circ} + \tan 45^{\circ} )\cdot \cot 37^{\circ} - 2\cos 60^{\circ}$

$\left(\frac{1}{\cos 245^{\circ}}+\frac{\sin 45^{\circ}}{\cos 45^{\circ}} \right)\cdot \left(\frac{\cos 37^{\circ}}{\sin 37^{\circ}} \right) - 2\cdot \cos 60^{\circ}$

$(-2.366 + 1 )\cdot (1.327) - 1$

$-2.813$

7 0

3 years ago

Write down two prime numbers that have a sum of 32

DaniilM [7]

19 and 13 can be the numbers

hope it helps

5 0

3 years ago

Read 2 more answers